PHP How right replace text on function?

Question

private function Photo($m,$photo){

  if($m == 'print'){
    print $photo; // or echo
  }
  else {
    return $photo;
  }
}

private function GetText(){
  ...
  ...
  $i = $res->fetch_assoc();
  $Text = $i["Text"];

    Now `$Text` have next:

     html text
     ....
     <p>%photo(2)%</p>
     <p>%photo(3)%</p>
     <p>%photo(4)%</p>
     ...
     html text

  echo $Text;
}

I would like replace text %photo(N)% (where N - it any number) on function Photo($m,N) (or function Photo(N)).

For this i use code:

$Text = preg_replace_callback("/\{photo\((\d+)\)\}/","Photo",$Text);

But it not work...

Tell me please how make it ?

P.S.: After replace $Text my example should been next:

html text
....
<p>2</p>
<p>3</p>
<p>4</p>
...
html text

Niet the Dark Absol · Accepted Answer · 2014-06-03 13:49:56Z

1

Photo is a method of the class, not a function in itself.

Try:

$Text = preg_replace_callback("/\{photo\((\d+)\)\}/",array($this,"Photo"),$Text);

For more on the callable typehint, check the documentation.

answered Jun 3, 2014 at 13:49

Niet the Dark Absol

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