How to remove preceding zeros in a string element from a Python list

Question

I have a list:

my_list = ['0300', '0023', '0005', '000030']

I want to remove the preceding zeroes in each string element from the list. So I want strip the 0s from the left side of the string.

Output would be like this:

my_list = ['300', '23', '5', '30']

I've tried this:

for x in my_list:
    x = re.sub(r'^0+', "", x) 
    print my_list

But it doesn't seem to work. Please help!

l = [a.lstrip("0") for a in l]

dano
– dano

2014-06-13 14:03:11 +00:00
Commented Jun 13, 2014 at 14:03 — dano
– dano, Commented Jun 13, 2014 at 14:03

thefourtheye · Accepted Answer · 2014-06-13 14:03:17Z

6

You can use str.lstrip like this

print [item.lstrip('0') for item in l]
# ['300', '23', '5', '30']

answered Jun 13, 2014 at 14:03

thefourtheye

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dano · Accepted Answer · 2014-06-13 14:16:42Z

1

Try:

list = [str(int(el)) for el in list]

Edit: pick the other answer, I'd prefer that one too :-)

edited Jun 13, 2014 at 14:16

dano

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answered Jun 13, 2014 at 14:03

HSquirrel

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1 Comment

HSquirrel Over a year ago

No it won't, I just tested it. However, the other solution is the better one :P. What you're thinking of is octal literals. Examples: int('0300') gives 300, int(0300) gives 192, int(0x300) gives 768. The quote marks make all the difference.

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