Parsing JS with regex python

Question

I have some javascript text to parse with python There is in js html elemet such variable:

this.products = ko.observableArray([#here is some json, #here is some json])

observableArray could be an holder for 1 json it will be observableArray({'id': '234234'}) or observableArray(['id': '3123123]), also it can hold infinite number of json per comma like in code pasted higher

how can i get this string with jsons with regexp i have try:

regex = re.compile('\n^(.*?)=(.*?)$|,',)
js_text = re.findall(regex, js)
print(js_text)

but im getting:

File "/usr/lib/python2.7/re.py", line 177, in findall return _compile(pattern, flags).findall(string) TypeError: expected string or buffer

"Parsing JS with regex" - DON'T YOU DARE!!! Use a JSON parser instead. — The Paramagnetic Croissant
– The Paramagnetic Croissant, Commented Jun 22, 2014 at 11:37
@user3477950 i need to get this string from large js file , then to parse with json — user3761151
– user3761151, Commented Jun 22, 2014 at 11:51

mhawke · Accepted Answer · 2014-06-22 11:56:22Z

1

js is not a string nor a buffer. Are you sure that js is a string (or a buffer)?

# no problem
>>> js = "this.products = ko.observableArray({'id': '234234'})"
>>> js_text = re.findall(regex, js)
>>> print(js_text)
[]

# argument is not a string nor a buffer (in this case None)
>>> js_text = re.findall(regex, None)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/mhawke/virtualenvs/urllib3/lib64/python2.7/re.py", line 177, in findall
    return _compile(pattern, flags).findall(string)
TypeError: expected string or buffer
>>> js_text = re.findall(regex, js)
>>> print(js_text)
[]

BTW, it's slightly nicer to call regex.findall(js).

And, there is a (different) problem with your regex pattern.

answered Jun 22, 2014 at 11:56

mhawke

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