Simple PHP Array Problem - IF EXIT

Question

how can i convert this into an array? if someone searches for "lo" he gets the text "no query", but how can i do this for more words? i tried it with array('1','2')..

if ($query == 'lo')
{
  exit ('No Query.');
}

i want something like this

if ($query == 'lo', 'mip', 'get')
{
  exit ('No Query.');
}

so, if someone types mip he gets the message.. thank you!!

jackbot · Accepted Answer · 2010-03-13 17:39:07Z

3

if ($query == 'lo' || $query == 'mip' || $query == 'get') {
    exit('No query');
}

Or if you might want to add many strings to check for, try using an array.

$bad_words = array('lo', 'mip', 'get', ... );
if (in_array($query, $bad_words)) {
    exit('No query');
}

Then adding new 'bad words' is as easy as adding them to the array.

answered Mar 13, 2010 at 17:39

jackbot

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2 Comments

lunohodov Over a year ago

Maybe using in_array(strtolower($query), $bad_words) would be better? Cheers

jackbot Over a year ago

@lunohodov yep, assuming no prior manipulation/validation has been done, that would be better

Sarfraz · Accepted Answer · 2010-03-13 17:38:24Z

0

Your array should look like this:

$array = array('lo', 'mip', 'get');

Now Search

if (in_array('mip', $array))
{
  echo 'We have a match';
}
else
{
  echo 'No match';
}

answered Mar 13, 2010 at 17:38

Sarfraz

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