Adding using a for loop in python

Question

I'm try to add some numbers to 36 in sequence. For example I have 36, then my list of number such as 10, 20, and 30. I want my program to add 36 to ten, take the sum of that, add it to 20, and so on. I'm probably making myself look like an idiot here, but I'm really trying to learn.

Here is one I tried:

x = [11, 152, 620, 805, 687, 1208, 866, 748, 421, 434, 67, 56, 120, 466, 143, 1085, 401]         
b = sum(36, x)
print b

or

x = [11, 152, 620, 805, 687, 1208, 866, 748, 421, 434, 67, 56, 120, 466, 143, 1085, 401]       
y = 0
for int in x:
    print y + x

Try sum([36] + x) or, better yet, 36 + sum(x).

user4815162342
– user4815162342

2014-07-04 21:28:12 +00:00
Commented Jul 4, 2014 at 21:28 — user4815162342
– user4815162342, Commented Jul 4, 2014 at 21:28

Ray Toal · Accepted Answer · 2014-07-04 21:38:45Z

2

Maybe it is not well known that sum takes a second parameter that defaults to zero, but your question is simply asking for this to be called out!

Try

sum(x, 36)

It actually works.

>>> sum([1,2,3], 36)
42
>>> sum([], 36)
36

See the docs.

It looks like when you tried sum(36, x) that you just had the parameters reversed. It is okay to say:

sum(x, start=36)

That does exactly what you want; it starts with 36 then accumulates all the values in x.

And it does it without a for loop, which is actually nice.

edited Jul 4, 2014 at 21:38

answered Jul 4, 2014 at 21:33

Ray Toal

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Comments

chepner · Accepted Answer · 2014-07-04 21:29:20Z

1

Short and sweet:

b = 36 + sum(x)

answered Jul 4, 2014 at 21:29

chepner

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1 Comment

Æther Over a year ago

Wow, I'm a fool! Thanks for the help! I will accept your answer once the site allows me.

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