I'm trying to create a list of even numbers from 1-100 by using a for loop on my variable list100.
list100 = range(101) for num in list100: list_even = [] if num % 2 == 0: list_even.append(num) print list_even
However, instead of getting [2,4,6,8,10,12,14 ....], I receive:
[0] [] [2] [] [4] [] [6] . . . .
Please help. Thank you!!
You are resetting the list at every iteration. Try:
list100 = range(101)
list_even = []
for num in list100:
if num % 2 == 0:
list_even.append(num)
print list_even
though as @koffein points out in another answer,
range(2,101,2)
is more idiomatic.
print needs to be moved out of the loop too.This way does not use a for loop, but is actually more idiomatic, I think.
# python 2.x
print range(2, 101, 2)
# python 3.x
print(list(range(2, 101, 2)))
Probably better to use list comprehension.
listeven = [x for x in range(101) if x % 2 == 0]
Nice and easy!
list100 = range(101)
list_even = []
for num in list100:
if num % 2 == 0:
list_even.append(num)
print list_even
this should work now. My fault also that i put the array inside loop so the item is resetting.
