Regex: Find & Replace in String

Question

I have a string

String customHtml = "<html><body><iframe src=https://zarabol.rediff.com/widget/end-of-cold-war-salman-hugs-abhishek-bachchan?search=true&header=true id=rediff_zarabol_widget name=rediff_zarabol_widget scrolling=auto transparency= frameborder=0 height=500 width=100%></iframe></body></html>";

I need to replace the last index of weburl with another string. In the above example replace

end-of-cold-war-salman-hugs-abhishek-bachchan

with

srk-confesses-found-gauri-to-be-physically-attractive

I tried using Lazy /begin.*?end/ but it fails. Any help will be highly appreciated. Thanks in advance.

You definitely need a html parser. Do not use regex for html content. It slows down. — Suresh Atta
– Suresh Atta, Commented Jul 22, 2014 at 7:27
I don't think regex is the right tool for parsing HTML. You might gain something from reading stackoverflow.com/q/1732348 — Dawood ibn Kareem
– Dawood ibn Kareem, Commented Jul 22, 2014 at 7:27
try using JSoup for parsing HTML instead of regex based match. — Ankur Shanbhag
– Ankur Shanbhag, Commented Jul 22, 2014 at 7:29
I think regex is the right choice because html parser can parse only the whole url in this case — yelliver
– yelliver, Commented Jul 22, 2014 at 7:30

Avinash Raj · Accepted Answer · 2014-07-22 07:39:05Z

2

Regex:

(?<=\/)[^\/]*(?=\?)

Java regex:

(?<=/)[^/]*(?=\\?)

Replacement string:

srk-confesses-found-gauri-to-be-physically-attractive

DEMO

Java code would be,

String url= "<html><body><iframe src=https://zarabol.rediff.com/widget/end-of-cold-war-salman-hugs-abhishek-bachchan?search=true&header=true id=rediff_zarabol_widget name=rediff_zarabol_widget scrolling=auto transparency= frameborder=0 height=500 width=100%></iframe></body></html>";
String m1 = url.replaceAll("(?<=\\/)[^\\/]*(?=\\?)", "srk-confesses-found-gauri-to-be-physically-attractive");
System.out.println(m1);

IDEONE

edited Jul 22, 2014 at 7:39

answered Jul 22, 2014 at 7:33

Avinash Raj

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1 Comment

Keppil Over a year ago

No need to escape forward slashes.

Bohemian · Accepted Answer · 2014-07-22 08:13:25Z

1

This should do it:

url = url.replaceAll("(?<=/)[^/?]+(?=\\?)", "your new text");

answered Jul 22, 2014 at 8:13

Bohemian♦

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Comments

user3440171 · Accepted Answer · 2014-07-22 08:05:01Z

0

Regex: [^/]*?(?:\?)

You must remove "/" from regex.

answered Jul 22, 2014 at 8:05

user3440171

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zx81 · Accepted Answer · 2014-07-22 08:09:40Z

0

As others have said, a DOM parser would be better. For completion, here is a regex solution that will work for your input:

String replaced = yourString.replaceAll("(https://\\S+/)[^?]+", 
                    "$1srk-confesses-found-gauri-to-be-physically-attractive");

Explanation

(https://\\S+/) captures to Group 1 the literal https://, any chars that are not white-spaces \S+, and a forward slash /
[^?]+ matches any chars that are not ? (the text to replace)
We replace with $1 Group 1 (unchanged) and the text you specified

answered Jul 22, 2014 at 8:09

zx81

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