Create Zip-File in java without using byte[]

Question

in my programm, I generate multiple CSV-Files which I want to publish on a Webpage as one .zip file. For that I want to use Java 1.6 on the server.

At the moment, I can create a .csv File without problems. Now I want to write the content of the BufferedWriter, I use to create the csv-File, to write directly into a Zip-File (without storing the csv File).

I found some tutorials like Creating zip archive in Java and http://www.mkyong.com/java/how-to-compress-files-in-zip-format/ And I want to do more or less the same in my Application, but I don't like the byte-Arrays.

Can I avoid this byte-Arrays?

If I understood your question, you want to create a zip without an existing file on the filesystem. This question shows how to create a zip file by directly writing a in-memory string to a zip entry (so you don't have to zip a file stored in the file system). And no, you can't skip byte arrays. — BackSlash
– BackSlash, Commented Aug 18, 2014 at 10:03

Daniel Puiu · Accepted Answer · 2018-06-12 11:19:03Z

1

You can use the new IO package in Java for working with Zip files.

Zip File System Provider is provided from Java 7 onwards.

Map<String, String> env = new HashMap<>(); 
env.put("create", "true");
// locate file system by using the syntax 
// defined in java.net.JarURLConnection
URI uri = URI.create("jar:file:/codeSamples/zipfs/zipfstest.zip");
try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
    Path externalTxtFile = Paths.get("/codeSamples/zipfs/SomeTextFile.txt");
    Path pathInZipfile = zipfs.getPath("/SomeTextFile.txt");          
    // copy a file into the zip file
    Files.copy( externalTxtFile,pathInZipfile, 
                StandardCopyOption.REPLACE_EXISTING ); 
}

edited Jun 12, 2018 at 11:19

Daniel Puiu

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answered Jun 12, 2018 at 9:52

dnavz28

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Comments

Siva Kumar · Accepted Answer · 2014-08-18 10:03:22Z

0

Its not possible since you are using OutStream. Because OutStreams are dealing with byte to write.

Normally two ways are I/O present. One is Stream based (Byte), another is Reader(Char) based. Zip only contains stream based implementation.

answered Aug 18, 2014 at 10:03

Siva Kumar

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1 Comment

waXve Over a year ago

That's not the answere I want to hear... OK so I have to handle with the bytes.

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