Parsing a XML string using JAXB

Question

I am using the JAXB parser to convert XML to a Java object. I have generated the JAXB files from the XML schema (XSD).

While passing the XML String , I defined xsi:noNamespaceSchemaLocation='Typetest.xsd'. So this will validate the XML document against the XML schema Typetest.xsd.

But my question is that I never defined the path for the JAXB parser to grab the schema file.

So how will JAXB determine the path ?

<book xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="TypeTest.xsd">
</book>

bdoughan · Accepted Answer · 2014-09-26 12:06:23Z

2

To enable validation on the unmarshal operation you must set an instance of Schema on the Unmarshaller.

Below is a link to an example on my blog:

http://blog.bdoughan.com/2010/12/jaxb-and-marshalunmarshal-schema.html

edited Sep 26, 2014 at 12:06

answered Sep 26, 2014 at 10:20

bdoughan

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3 Comments

jaggs Over a year ago

Thanks for your reply .I have no issues with the validation against the schema.But i am just curious on where actually the unmarshaller finds the path from? from my code , i just pass the xml string to the unmarshaller .Can you help to explain with an example?

bdoughan Over a year ago

@jegadees - The Unmarshaller doesn't find the path. You need to create an instance of Schema and set it on the Unmarshaller yourself. I have added a link to an example in my answer.

jaggs Over a year ago

exactly the answer i am looking for..Thanks

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