Android: How to parse JSON Array of Array of objects

Question

Can any body tell me how I parse this type of json in android?

[
   [
      {
         "condition_id":"1",
         "condition_name":"Type 1 Diebetics"
      }
   ],
   [
      {
         "condition_id":"2",
         "condition_name":"Type 2 dypatise"
      }
   ]
]

Thanks

Solved

Thank you very much nayoso Its worked for me.

String jsonString = "[
   [
      {
         "condition_id":"1",
         "condition_name":"Type 1 Diebetics"
      }
   ],
   [
      {
         "condition_id":"2",
         "condition_name":"Type 2 dypatise"
      }
   ]
]";
JSONArray jsonArray = new JSONArray(jsonString);
for(int i=0;i<jsonArray.length(),i++) {
   JSONArray childJsonArray = jsonArray.getJSONArray(i);
   JSONObject contentJsonObject = childJsonArray.getJSONObject(0);
   String conditionID = contentJsonObject.getString('condition_id');
   String conditionName = contentJsonObject.getString('condition_name');
   Log.i("TAG","Index "+i+" condition_id "+conditionID+" condition_name "+conditionName);
}

You can do this easily with the org.json library. The whole thing is a JSONArray; at position 0 (use .get(0)) you have another JSONArray; at position 0 of that, you have a JSONObject, which maps keys to values (use .getString()).

Thanks chiastic-security also for making me understand.

This pretty much explains it.

SME_Dev
– SME_Dev

2014-09-30 09:32:52 +00:00
Commented Sep 30, 2014 at 9:32 — SME_Dev
– SME_Dev, Commented Sep 30, 2014 at 9:32
Thanks for your Response I read it out.

Husnain Aslam
– Husnain Aslam

2014-09-30 09:34:04 +00:00
Commented Sep 30, 2014 at 9:34 — Husnain Aslam
– Husnain Aslam, Commented Sep 30, 2014 at 9:34
why given me down vote on that question?

Husnain Aslam
– Husnain Aslam

2014-09-30 09:58:35 +00:00
Commented Sep 30, 2014 at 9:58 — Husnain Aslam
– Husnain Aslam, Commented Sep 30, 2014 at 9:58

Niko Adrianus Yuwono · Accepted Answer · 2014-09-30 09:37:35Z

2

You can use built in JSONArray and JSONObject classes

String jsonString = "[
   [
      {
         "condition_id":"1",
         "condition_name":"Type 1 Diebetics"
      }
   ],
   [
      {
         "condition_id":"2",
         "condition_name":"Type 2 dypatise"
      }
   ]
]";
JSONArray jsonArray = new JSONArray(jsonString);
for(int i=0;i<jsonArray.length(),i++) {
   JSONArray childJsonArray = jsonArray.getJSONArray(i);
   JSONObject contentJsonObject = childJsonArray.getJSONObject(0);
   String conditionID = contentJsonObject.getString('condition_id');
   String conditionName = contentJsonObject.getString('condition_name');
   Log.i("TAG","Index "+i+" condition_id "+conditionID+" condition_name "+conditionName);
}

answered Sep 30, 2014 at 9:37

Niko Adrianus Yuwono

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2 Comments

Husnain Aslam Over a year ago

I am getting this exception org.json.JSONException: Value [{"condition_id":"2","condition_name":"Type 2 dypatise"}] at 1 of type org.json.JSONArray cannot be converted to JSONObject

Husnain Aslam Over a year ago

also FATAL EXCEPTION: AsyncTask #1 java.lang.RuntimeException: An error occured while executing doInBackground() and Caused by: java.lang.NoSuchMethodError: org.json.JSONArray.<init>

chiastic-security · Accepted Answer · 2014-09-30 09:37:10Z

1

You can do this easily with the org.json library. The whole thing is a JSONArray; at position 0 (use .get(0)) you have another JSONArray; at position 0 of that, you have a JSONObject, which maps keys to values (use .getString()).

answered Sep 30, 2014 at 9:37

chiastic-security

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Comments

AndyN · Accepted Answer · 2014-09-30 09:40:22Z

1

JSONArray jsonarray=new JSONArray(your_data);
                for(int i=0;i<jsonarray.length();i++)
                {
                    JSONArray array=jsonarray.getJSONArray(i);
                    for(int j=0;j<array.length();j++)
                    {
                        JSONObject jsonObject=array.getJSONObject(0);
                        String ConditionId=jsonObject.getString("condition_id");
                        String ConditionName=jsonObject.getString("condition_name");
                    }
                }

answered Sep 30, 2014 at 9:40

AndyN

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Comments

Neetu Shrivastava · Accepted Answer · 2014-09-30 09:43:39Z

1

      JSONArray jsonArray = new JSONArray("Your Data");
      JSONArray tempArray ; 
      net.sf.json.JSONObject tempJson ;
      for(int i = 0 ; i < jsonArray.length() ; i++)
      {
          tempArray =  jsonArray.getJSONArray(i);

          tempJson =  tempArray.getJSONObject(0);

          tempJson.get("condition_id");

          ....data So On
      }

answered Sep 30, 2014 at 9:43

Neetu Shrivastava

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Comments

sschrass · Accepted Answer · 2014-09-30 10:00:55Z

1

try this

String data = ""; //your json data string
JSONArray jarray = new JSONArray(data);

for(int i = 0;i < jarray.length(); i++) {
    JSONArray jarry1 = jarray.getJSONArray(i);
    for(int j = 0; j < jarry1.length(); j++) {
        JSONObject jobj = jarry1.getJSONObject(0);
        String ConditionId = jobj.getString("condition_id");
        String ConditionName = jobj.getString("condition_name");
    }
}

edited Sep 30, 2014 at 10:00

sschrass

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answered Sep 30, 2014 at 9:37

Jatin

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