Below is the method add() of Java List Interface; if I loop through it 7 times adding i to the 0th position like so.
for (int i = 0; i < 7; i++) {
list.add(0, i);
}
Wouldn't it overwrite the value at that position, so I would end up with just one value of 6 in the list? Am I right, in assuming that?
No, if you add at a position, it shifts everything starting at that position to the right.
So if you actually did this, you should end up with the following list:
[6, 5, 4, 3, 2, 1, 0]
Read the API: http://docs.oracle.com/javase/7/docs/api/java/util/List.html#add%28int,%20E%29
Or better yet, give it an actual try.
according to this doc on list List for Java it pushes the element to the right of the list adding one to the indices
Suppose we have,
mylist = ["Bashful","Awful","Jumpy","Happy"]
then,
mylist.add(2,"Doc")
makes the ArrayList
mylist = ["Bashful","Awful","Doc","Jumpy","Happy"]
Notice that the indices of "Jumpy" and "Happy" have changed from 2 to 3, and 3 to 4, accordingly.
