Why can't I initialize my array of structures containing function pointers in C?

Question

my_functions.h

void * f1 (int * param);
void * f2 (int * param);
void * f3 (int * param);
void b1(int * param);
void b2(int * param);
void b3(int * param);

my_prog.c

#include <my_functions.h>

// Typedef my function pointers
typedef void * (*foo)(int*);
typedef void (*bar)(int*);

// Declare the structure that will contain function pointers
typedef struct _my_struct
{
    int tag;
    foo f;
    bar b;
}my_struct;

// Declare and initialize the array of my_struct
my_struct array[] =
{
    {1, f1, b1},
    {2, f2, b2},
    {3, f3, b3}
};

Compiler says:

warning: initialization from incompatible pointer type

I looked at:

But I still can't see what I missed...
For me, all the types and the functions are known by the time I try to initialize my array.
Can't the init be done outside a function ?

[EDIT] I am on Linux, using an embedded version for arm of GCC 4.9.

For me too. At which line do you get the error ? Which compiler/platform/OS are you using ? — Jabberwocky
– Jabberwocky, Commented Oct 21, 2014 at 15:26
I am reviewing my code as I simplified it in my post... I might have missed something. I get the warning at all the closing braces of the {x,fx,bx} — n0p
– n0p, Commented Oct 21, 2014 at 15:28
Actually it doesn't throw any warning. The compiler I use is to blame, cf my own answer. — n0p
– n0p, Commented Oct 21, 2014 at 15:57

n0p · Accepted Answer · 2014-10-21 15:59:43Z

2

Ok so my code works just fine on my PC, it is actually the arm-gcc compiler that I use for my embedded target that throw this error because it seems it can't recognize the type of the function pointers without an explicit cast:

Here is the fix:

my_struct array[] =
{
    {1, (foo)f1, (bar)b1},
    {2, (foo)f2, (bar)b2},
    {3, (foo)f3, (bar)b3}
};

answered Oct 21, 2014 at 15:59

n0p

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