Comparing two JsonArray nodes in Java

Question

I have a method that gets two Json nodes that should be Json array nodes of different sizes. I need to check if ArrayA contains all the elements of ArrayB. How do I do that?

private boolean isContains (JsonNode ArrayA, JsonNode ArrayB) {

    if (ArrayA.isArray() && ArrayB.isArray()) {
        // Here goes the missing code.
    }
}

By documentation equals should work in depth, see jackson.codehaus.org/1.7.9/javadoc/org/codehaus/jackson/… — Marek Sebera
– Marek Sebera, Commented Nov 9, 2014 at 20:17
They are not equal. In Java, we have a method list.contains(anotherList). Is there something similar in Jackson? — Alex
– Alex, Commented Nov 9, 2014 at 20:25
I misunderstood your question. The other answers are appropriate. — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Nov 9, 2014 at 21:08

Gábor Bakos · Accepted Answer · 2014-11-09 21:06:29Z

2

The JSON Patch reverse part might do what you are looking for.

See: https://github.com/fge/json-patch#json-diff-factorization

Edit: It is as easy as:

JsonNode diff = JsonDiff.asJson(first, second);

And than you can check whether diff contains removes or adds or both.

edited Nov 9, 2014 at 21:06

answered Nov 9, 2014 at 20:33

Gábor Bakos

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Comments

ced-b · Accepted Answer · 2014-11-10 03:25:22Z

0

There seems to be no inbuilt method I can see, but JsonNode implements Iteratable so you can loop through both and do a compare. Something along the lines of:

boolean matches = true;

for (JsonNode nodeB : arrayB)
{
   boolean matchesInternal = false;

   for (JsonNode nodeA : arrayA)
   {
      if (nodeA.equals(nodeB))
      {
          matchesInternal = true;
          break;
      }
   }

   if (!matchesInternal) {
      matches = false;
      break;
   }
}

return matches;

edited Nov 10, 2014 at 3:25

answered Nov 9, 2014 at 20:30

ced-b

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4 Comments

Alex Over a year ago

could it be I have no matches() method?

Alex Over a year ago

I used nodeA.**asText()**.equals(nodeB.**asText()**) to compare the nodes as strings and it worked just fine. Thanks a lot.

Gábor Bakos Over a year ago

@Alex if you check the asText() documentation, you will see it will return empty strings for compound elements, so that is a not too good solution, different things will be considered equals.

ced-b Over a year ago

@Alex Sorry, I mistyped that. equals would be correct. I don't know that you have to call asText().

Gopi Vishwakarma · Accepted Answer · 2015-07-09 14:21:32Z

0

You can use zjsonpatch library, which presents the diff information in accordance with RFC 6902 (JSON Patch). Its very easy to use. Please visit its description page for its usage. This library is better than fge-json-patch (which was mentioned in above answer) because it can detect correctly items being inserted/removed from arrays.

answered Jul 9, 2015 at 14:21

Gopi Vishwakarma

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Comments

Timur Kondratyev · Accepted Answer · 2021-05-26 11:20:59Z

0

For those who faced the same problem but prefer more flat code. You can use the Apache Commons's IterableUtils.toList() to convert the ArrayNode#elements() to List and then perform List#containsAll() operation to check whether they contain the same elements. It will look like this:

sourceArray.size() == targetArray.size() && IteratorUtils.toList(sourceArray.elements()).containsAll(IteratorUtils.toList(targetArray.elements()))

answered May 26, 2021 at 11:20

Timur Kondratyev

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