PHP variable scope after multiple includes

Question

Let's say I hava a page index.php and in it I execute:

require_once("file1.php");
echo $myVar;

in file1.php I have:

require_once("file2.php");

and in file2.php I have

$myVar = "test";

After executing this script, index.php can't get to $myVar and outputs undefined variable. Any reason on that ?

Something else is affecting $myVar that you're not putting here. As it stands this problem can't be reproduced by your example. — sjagr
– sjagr, Commented Nov 17, 2014 at 18:23
Works for me. There must be some other code that is relevant. — Tim Seguine
– Tim Seguine, Commented Nov 17, 2014 at 18:23
Are you including file1.php or file2.php in some other location first? require_once will only include the file if it has not already been included. — mcrumley
– mcrumley, Commented Nov 17, 2014 at 18:25
first try it guys, and then say it's something wrong with my code. I've been doing PHP for 5 years but it's the first time when I try 2-level include var scope... — silver14_
– silver14_, Commented Nov 17, 2014 at 18:40

Marc B · Accepted Answer · 2014-11-17 18:26:20Z

2

require/include act as if the contents of the file being included were literally cut/pasted into the place where the include directive is. Your variable will work, unless something else is trashing it between the include calls.

e.g.

core.php:

<?php
$foo = 'bar';

file1.php:

include('core.php');
$foo = 'baz';

file2.php

echo $foo; // undefined
include('core.php');
echo $foo; // outputs bar
include('file1.php');
echo $foo; // outputs baz

answered Nov 17, 2014 at 18:26

Marc B

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2 Comments

silver14_ Over a year ago

I know that's how it's supposed to be but it doesn't happen to me. I copy/paste your example and the same behaviour occurs. Where I include a variable from a second file it doesn't see it. Only on the first level include

Valera Leontyev Over a year ago

@silver14_, try to replace require_once to require first of all. Look at comments to your question.

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