Java remove duplicates from array using loops

Question

This is my current attempt to remove duplicates from an array holding integers, but this does not give me any results. It simply prints out nothing. Any help would be greatly appreciated.

    public static void duplicate(int numbers[], int size)
    {
      for (int i = 0; i < size; i++){
        boolean duplicate = false;
        int b = 0;
        while (b < i){
          if (numbers[i] == numbers[b])
             duplicate = true;
          b++;}
        if (duplicate = false)
          System.out.print(numbers[i] + " ");}
    }

this should work fine. just change = with == in the last if. — İsmet Alkan
– İsmet Alkan, Commented Nov 18, 2014 at 15:44

DJ Burb · Accepted Answer · 2014-11-18 15:42:26Z

1

Try this:

public static void duplicate(int numbers[], int size)
{
  for (int i = 0; i < size; i++){
    boolean duplicate = false;
    int b = 0;
    while (b < i){
      if (numbers[i] == numbers[b])
         duplicate = true;
      b++;}
    if (duplicate == false)
      System.out.print(numbers[i] + " ");}
}

You need to use == not = in your if statement.

answered Nov 18, 2014 at 15:42

DJ Burb

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Ankur Singhal · Accepted Answer · 2014-11-18 15:47:37Z

0

You can also make use of HashSet or LinkedHashSet to Preserve the ordering

public void removeDupInIntArray(int[] ints){
    Set<Integer> setString = new LinkedHashSet<Integer>();
    for(int i=0;i<ints.length;i++){
        setString.add(ints[i]);
    }
    System.out.println(setString);
}

answered Nov 18, 2014 at 15:47

Ankur Singhal

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Comments

wwSlayerww · Accepted Answer · 2014-11-18 19:40:42Z

0

The best choice would be to use the Sets(Hash Linkedhash) so duplicates can be avoided

answered Nov 18, 2014 at 19:40

wwSlayerww

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