REGEX pattern for javascript

Question

I have this pattern to be tested in javascript using REGEX:

nn.nnn.nnn./nnnn-nn

where n can be any integer between 0-9.

And I have this regex that works.

[0-9]{2}[.][0-9]{3}[.][0-9]{3}\/[0-9]{4}[-][0-9]{4}

Is there another more elegant way to rewrite this expression to grab the same pattern?

you have a fixed and clean pattern to match, why bothering complicating the regex? — DRC
– DRC, Commented Dec 2, 2014 at 18:40

plalx · Accepted Answer · 2014-12-02 18:44:02Z

1

There's a few possible simplifications:

[0-9] -> \d
[.] -> \.
[-] -> -
nnn.nnn. -> (\d{3}\.){2}

nn.nnn.nnn./nnnn-nn -> \d{2}\.(\d{3}\.){2}\/\d{4}-\d{2}

Your pattern asks for 4 digits at the end, but not your data sample. I followed the sample.

answered Dec 2, 2014 at 18:44

plalx

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2 Comments

IgorAlves Over a year ago

Hi plalx, this part was what I was looking for (someting){2}, because I realise that the code I wrote was duplicated, and it could be better written. I had to change a little from your code that is good. I only changed the position of the second \. and deleted the first one. The final is like this: '\d{2}(\.\d{3}){2}\/\d{4}-\d{2}'

IgorAlves Over a year ago

the pattern should be nn.nnn.nnn/nnnn-nn not nn.nnn.nnn./nnnn-nn

DRC · Accepted Answer · 2014-12-02 18:43:52Z

0

Read my comment, and probably you should correct it to something like:

\d{2}\.\d{3}\.\d{3}\.\/\d{4}-\d{2}

answered Dec 2, 2014 at 18:43

DRC

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1 Comment

IgorAlves Over a year ago

hi DRC I was tring to avoid repeat pattern like \.\d{3} 2 times . So the answer was made by plalx only (something){2}

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