AngularJS - $timeout is not a function

Question

I try to inject $timeout in the run function but I get that it is not a function when I try to call it. Why ?

var mainApp = angular.module('mainApp', ['ngRoute', 'ngAnimate', 'ui.bootstrap', ngCookies']);

mainApp.run(['$rootScope', '$location', '$timeout'
        function ($rootScope, $location, $route, authService, $timeout) {
...
}]);

there is lot of syntax error in this code. correct it and try again — simon
– simon, Commented Dec 3, 2014 at 12:59

CKK · Accepted Answer · 2014-12-03 13:08:46Z

19

mainApp.run(['$rootScope', '$location', '$timeout'
        function ($rootScope, $location, $route, authService, $timeout) {
...
}]);

should be:

mainApp.run(['$rootScope', '$location', '$route', 'authService', '$timeout',
        function ($rootScope, $location, $route, authService, $timeout) {
...
}]);

see 'The array annotation' part here:

https://docs.angularjs.org/api/auto/service/$injector

edited Dec 3, 2014 at 13:08

CKK

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answered Dec 3, 2014 at 12:59

Rasalom

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Comments

kubuntu · Accepted Answer · 2014-12-03 13:04:51Z

3

When you annotate function with names of dependencies, the order of appearance should match.

...
mainApp.run(['$rootScope', '$location', '$route', '$timeout', 'authService', 
        function ($rootScope, $location, $route, $timeout, authService) {
...
}]);

answered Dec 3, 2014 at 13:04

kubuntu

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