PHP function which executes provided function with provided arguments

Question

Is the a way in php to create a function which executes provided function (as an arguments) with provided argument (of the provided function - as an array).

Here is some code:

class Worker
{
    public function execute($func, $paramsArr)
    {
        php_func_executer($func, $paramsArr); //the function that I would like to have
    }
}

in other php file I will do as follow:

Class SomeClass 
{
    public function test($varA, $varB)
    {
         //do something
    }

    public function exeText()
    {
       ...
       $worker = new Worker();
       $worker->execute(test, [$varA, $varB]);
    }
}

I know about call_user_func_array but here I don't want to pass the name of the function (as string), I want to pass the function itself (as seen in the code above)

Thanks!

first argument of call_user_func_array is any callable, so you can pass a function to it, not name only. — u_mulder
– u_mulder, Commented Dec 6, 2014 at 17:39
even if it is not in the same file? the second argument is an array of arguments? — vlio20
– vlio20, Commented Dec 6, 2014 at 17:40
You should explain what do you mean by passing a function? You don;t want to pass a string with function name, so what do you want to pass - array? variable with anonymous function or what? — u_mulder
– u_mulder, Commented Dec 6, 2014 at 17:44
You can see in my second code block what I meant, but I think the answer is already posted here. Thanks — vlio20
– vlio20, Commented Dec 6, 2014 at 17:48

Sampath Liyanage · Accepted Answer · 2014-12-06 17:44:43Z

1

You can pass the function name as a string and call it.

function execute($func, $paramsArr)
    {
        $func($paramsArr[0], $paramsArr[1]);
    }

function func($par1, $par2)
    {
        echo $par1." ".$par2;
    }


execute('func' , array('a','b'));

answered Dec 6, 2014 at 17:44

Sampath Liyanage

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Comments

Jakub Filipczyk · Accepted Answer · 2014-12-06 17:43:24Z

1

call_user_func_array will do the job

$func = function($a, $b) {
    return $a+$b;
};

echo call_user_func_array($func, [1, 2]); // 3

answered Dec 6, 2014 at 17:43

Jakub Filipczyk

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1 Comment

DarkBee Over a year ago

I downvoted this because OP said this :

I know about call_user_func_array but here I don't want to pass the name of the function (as string), I want to pass the function itself (as seen in the code above)

. So this is not an answer to the question

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