Can I do this in C++ (if yes, what is the syntax?):
void func(string* strs) {
// do something
}
func({"abc", "cde"});
I want to pass an array to a function, without instantiating it as a variable.
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4 Answers
It can't be done in the current C++, as defined by C++03.
The feature you are looking for is called "compound literals". It is present in C language, as defined by C99 (with C-specific capabilities, of course), but not in C++.
A similar feature is planned for C++ as well, but it is not there yet.
answered May 4, 2010 at 16:46
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1 Comment
Albert
What about C++11?
I don't think you can do that in C++98, but you can with initializer_lists in C++1x.
2 Comments
Dennis Zickefoose
I love initializer_lists so much.
Albert
Your linked example uses
std::vector. How can you do the same for arrays?Use a variadic function to pass in unlimited untyped information into a function. Then do whatever you want with the passed in data, such as stuffing it into an internal array.
Comments
As written, you can't do this. The function expects a pointer-to-string. Even if you were able to pass an array as a literal, the function call would generate errors because literals are considered constant (thus, the array of literals would be of type const string*, not string* as the function expects).
1 Comment
yegor256
If I don't instantiate a variable, it still has a pointer (address).