Convert a string in a few int between commas in python

Question

I am getting a number from a csv file to a list and would like to compare these numbers to other numbers, how can I achieve this?

num = [2,32,31,23,12,32]

csvnumber= ['23,43,41,21,34']

How do I convert the csv number into ints to compare with my num list?

whoan · Accepted Answer · 2015-01-15 03:27:14Z

2

You can do it with list comprehensions and the int factory function:

[ int(i) for i in csvnumber[0].split(',') ]

>>> csvnumber=['23,43,41,21,34']
>>> [ int(i) for i in csvnumber[0].split(',') ]
[23, 43, 41, 21, 34]

answered Jan 15, 2015 at 3:01

whoan

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Comments

user4447887 · Accepted Answer · 2015-01-15 02:52:18Z

1

x= ['23,43,41,21,34']

t=list(map(int, x[0].split(',')))

print (t)

Assume your list has only one element as your example.Output:

>>> 
[23, 43, 41, 21, 34]
>>>

Then reach each element in the list t with a for loop and append them to your list num.

answered Jan 15, 2015 at 2:52

user4447887

Malik Brahimi · Accepted Answer · 2015-01-15 03:04:02Z

0

Just make a new list, split the current list at the commas, and append the items as integers like so:

new_csvnumber = []

for i in csvnumber[0].split(','):
    new_csvnumber.append(int(i))

answered Jan 15, 2015 at 2:56

Malik Brahimi

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