I am tring to write a list of Node (xml's node) to xml file.
By writing:
val xml = <x>{nodes}</x>
where nodes are the list of nodes- I am getting all the nodes in one line .
What can I do to print every node in a new line?
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1 Answer
Here's the answer. In short, you can scala.xml.PrettyPrinter for your purposes. You should also remember (you probably do) that these classes are shipped in a separate library as of 2.11 release.
E.g.:
scala> val printer = new scala.xml.PrettyPrinter(80, 2)
scala> val nodes = List(
<lol>node level 1</lol>,
<bar><foo>node level 2</foo></bar>
)
scala> printer.formatNodes(nodes)
res1: String =
<lol>node level 1</lol><bar>
<foo>node level 2</foo>
</bar>
Actually, when I look at the result, I see that it differs somewhat from the desired output. I'd recommend using a little bit longer, but more matching to your expectations, variant:
nodes.map(node => printer.format(node)).mkString("\n")
That will separate each node by \n:
<lol>node level 1</lol>
<bar>
<foo>node level 2</foo>
</bar>
6 Comments
user3725190
the command "res0.format Nodes(nodes)" doesn't work - it asks for more parameters - do you know why?
tkroman
What library version do you have? Can you share the exact version of the code that doesn't work for you?
user3725190
"scala-xml" % "1.0.2"
tkroman
Hmm, that's strage. Maybe try to refresh your project or make sure you've got binary compatible builds of the libraries. Also, note that I updated the answer to match your question more precisely and the new variant doesn't use
formatNodes. Anyway, you should check your libraries' compatibility.user3725190
in format or in formatNode it asks to send not just the node (or nodes) but a Binder as well...
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