Remove part of URL using PHP (Zend FrameWork)

Question

my link is like this :

http://website.com/test1/test2/public/books/detail/page_id/number/page/2

I want to remove page and 2 and convert it to :

http://website.com/test1/test2/public/books/detail/page_id/number

I can define last part of URL with :

$uri = Zend_Controller_Front::getInstance()->getRequest()->getRequestUri();
$part = basename($uri);

or define another part like this :

$parts = Explode('/', $uri);
    $id2 = $parts[count($parts) - 2];
    $id1 = $parts[count($parts) - 1];

but I have problems to remove that

ThomasMo__ · Accepted Answer · 2015-01-19 14:19:54Z

2

$uri = $this->serverUrl(true);    
$parts = Explode('/page/', $uri);

the $parts[0] will be the good link you want

answered Jan 19, 2015 at 14:19

ThomasMo__

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Comments

Amit Kriplani · Accepted Answer · 2015-01-21 16:52:27Z

0

I think, for your case, this should be in your controller:

$url = Zend_Controller_Front::getInstance()->getBaseUrl() .
"books/detail/page_id/" . $this->getRequest()->getParam('page_id');

PS: Syntax will be different if you are in a view script, in which case you should create a view helper anyway or you can do it in controller and assign to view.

answered Jan 21, 2015 at 16:52

Amit Kriplani

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