CakePHP easy way to use different values in select input

Question

I got a little "problem" with CakePHP. My code is working fine, but I am looking for a way to shorten the code.

I have a model called "Document" and it "belongsTo" several "User"s.

creator
editor
responsiblePerson

In my Controller I use the following code to load a list of all the available users:

$creators= $this->Document->Creator->find('list');
$editors= $this->Document->Editor->find('list');
$responsiblepersons= $this->Document->Responsibleperson->find('list');
$this->set(compact('creators','editors','responsiblepersons');

Now I can use this code in my views:

echo $this->Form->input($creator_id);
echo $this->Form->input($editor_id);
echo $this->Form->input($responsibleperson_id);

This is working fine, but is it really necessary to find all 3 lists? In my controller $creators, $editors & $responsiblepersons contain all the same elements. Overall one "Document" is connected to 6 different "User"s, so this is really bloating my code.

Any idea? Thanks!

are creator, editor and responsiblePerson aliases to the same model? — Colonel Mustard
– Colonel Mustard, Commented Jan 22, 2015 at 19:37

floriank · Accepted Answer · 2015-01-22 15:26:12Z

1

If they all are associated with the same table and model than just do:

$users = $this->Document->Creator->find('list');

And use the same list everywhere where you need the same list in the views.

answered Jan 22, 2015 at 15:26

floriank

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2 Comments

conehead Over a year ago

Same table and model yes, but 3 different fields. creator_id, editor_id and responsibleperson_id. So I need something like this $this->Form->input('creator_id',$users)

floriank Over a year ago

Check the documentation. book.cakephp.org/2.0/en/core-libraries/helpers/form.html 2nd arg of input() is an options array. 'type' => 'select', 'options' => $list is needed for a select input.

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