Create a json object with array of arrays in PHP

Question

I'm using array_add($array, 'key', 'value'); to create the data structure.

foreach ($archives as $archive){
    $results = array_add($results, $archive->year, 
              array($archive->month => array('name' => $archive->month_name)));
}

If i json_encode()the $results i get this output:

{ 
   2015: {
       02: {name:'February'}
   }
}

But i want something like:

{
   2015: {
       02: {name:'February'},
       01: {name:'January'}
   }
}

And of course this should works for different years too.

array_add isn't a core php function, can you show the function aswell? Besides $results is overwritten in every iteration. — Daan
– Daan, Commented Feb 10, 2015 at 15:17
Why are you using a (IMHO pointless, and messy-looking) function (array_add), when you could just write $results[$archive->year] = array($archive->month => array('name' => $archive->month_name));? Oh, and could it be that "January" isn't int $results because it's not in the $archives to begin with? check those values, too — Elias Van Ootegem
– Elias Van Ootegem, Commented Feb 10, 2015 at 15:19
@EliasVanOotegem with your code i get the same output but with January and not February. — Christopher
– Christopher, Commented Feb 10, 2015 at 15:31
@idknow: Because you'd need to check if $results[$archive->year] doesn't already exist, if it does, your code currently reassigns it (overwriting the array that it already holds), I'll post an answer — Elias Van Ootegem
– Elias Van Ootegem, Commented Feb 10, 2015 at 15:33

Elias Van Ootegem · Accepted Answer · 2015-02-10 15:35:48Z

1

In response to my comments - here's what I'd do:

foreach ($archives as $archive)
{
    if (!isset($results[$archive->year]))
    {//if the year-key doesn't exist yet, create it
     //if it already exists, this part will be skipped
        $results[$archive->year] = array();
    }
    //then add the values
    $results[$archive->year][$archive->month] = array(
        'name' => $archive->month_name
    );
}

That's all there is to it, no need for a home-made function or anything like that

answered Feb 10, 2015 at 15:35

Elias Van Ootegem

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Bharat Paudyal · Accepted Answer · 2015-02-10 15:19:44Z

0

How about array_push($array, 'key', 'value');

answered Feb 10, 2015 at 15:19

Bharat Paudyal

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1 Comment

Elias Van Ootegem Over a year ago

That won't work at all, that'll push 'key' and 'value' as separate values onto $array consecutively see the manual

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