I have an output as below:
output = test:"<no-cjar> mxy 3044 jpg fasst_st
I want to read the output and store only the value that comes after 'mxy' and before 'jpg'. The value is always an integer.
I used something like:
value = re.findall(r"mxy \d+", output)
which I think will return 'mxy 3044'. I am not too certain if this is the best way. As I would probably have to split this again.
Is this right and is there another way i can do the same. Thanks in advance.
Use capturing group.
value = re.findall(r"mxy\s*(.*?)\s*jpg", output)
\s* matches zero or more spaces. OR r"mxy\s*(\d+)\s*jpg"
Example:
>>> re.findall(r"mxy\s*(.*?)\s*jpg", 'test:"<no-cjar> mxy 3044 jpg fasst_st')
['3044']
Alterantive approach, assuming that the the format of your string does not change, i.e. it has mxy followed by space and 4 digit number.
output = "<no-cjar> mxy 3044 jpg fasst_st"
n = int(output.split('mxy')[1][0:6])
print(n) # gives 3044
Just different way of doing the same thing, but without regex.
(?<=mxy )\d+