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what is going wrong with the below code?

Even if I pass the value as "aa" or "a", matchingArray is null.

Probably something is going wrong with the usage of variable in the regular expression.

var gEnLowercase = "a-z";
var gLanguageLowercase = "([" + gEnLowercase + "]";
gLanguageLowercase = gLanguageLowercase + "{0 , " + aLength + "})";
var filter = new RegExp(gLanguageLowercase);
var matchingArray = aValue.match(filter); // filter value => /([a-z]{0,10})/
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  • try to use this: var matchingArray = filter.match(aValue); Commented Feb 20, 2015 at 7:42

3 Answers 3

1

remove the extra space after 0 in the gLanguageLowercase ...it should be

gLanguageLowercase = gLanguageLowercase + "{0," + aLength + "})";
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var gEnLowercase = "a-z";
var gLanguageLowercase = "([" + gEnLowercase + "]";
gLanguageLowercase = gLanguageLowercase + "{0," + 3 + "})";
var filter = new RegExp(gLanguageLowercase);
console.log(filter);
var matchingArray = "sds".match(filter);
console.log(matchingArray); 

remove the extra spaces

Comments

0

You have to use filter.exec(aValue); instead of aValue.match(filter); Besides there are extra spaces in your regexp.

var gEnLowercase = "a-z";
var aLength = 10;
var gLanguageLowercase = "([" + gEnLowercase + "]";
gLanguageLowercase = gLanguageLowercase + "{0," + aLength + "})";
var filter = new RegExp(gLanguageLowercase);
var matchingArray = filter.exec(aValue); // filter value => /([a-z]{0,10})/

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