SyntaxError: Unexpected token at Object.parse AngularJS

Question

In my AngularJS application, when I trying to get data with new line from database, I get the following error :

 SyntaxError: Unexpected token 
at Object.parse (native)
at Object.oc [as fromJson] (http://localhost:8080/pjib/js/angular.min.js:14:156)
at new <anonymous> (http://localhost:8080/pjib/admin_pbjib/news/index.php:191:34)
at Object.e [as invoke] (http://localhost:8080/pjib/js/angular.min.js:37:96)
at $get.z.instance (http://localhost:8080/pjib/js/angular.min.js:76:210)
at http://localhost:8080/pjib/js/angular.min.js:59:164
at s (http://localhost:8080/pjib/js/angular.min.js:7:408)
at v (http://localhost:8080/pjib/js/angular.min.js:59:148)
at g (http://localhost:8080/pjib/js/angular.min.js:52:9)
at g (http://localhost:8080/pjib/js/angular.min.js:52:26)

My code (php):

 $getData = json_encode(GetAllDataFromServer($table_name));

JSON encoded output string :

 [  
   {  
      "news_id":"1",
      "heading":"In purto percipit ......t",
      "news_body":"In purto percipit nam, .........",
      "news_img":"",
      "create_date":"2015-02-21",
      "display_status":"Yes"
  },
  {  
      "news_id":"2",
      "heading":"Habemus adipisci ....",
       "news_body":"In .... some string .... reque choro.\r\n \r\nHabemus adipisci .... some string .... dissentiunt.\r\n \r\nVel aliquid .... some string ....  disputando te cum.\r\n \r\nIn usu .......",
      "news_img":"",
      "create_date":"2015-02-21",
      "display_status":"No"
   }
]

My AngularJS code :

 // only problem when '\r\n' appear in the json object(table column)
 $scope.news = angular.fromJson('<?=$getData ?>');

Thanks in advance!!!

sabbir · Accepted Answer · 2015-02-24 08:41:23Z

1

I solve my problem using the following code :

php code :

$getData = json_encode(GetAllDataFromServer($table_name));

After encoding db info into json fotmat, just do the following code.

AngularJS/JavaScript Code :

scope.news = <?=$getData ?>;

answered Feb 24, 2015 at 8:41

sabbir

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1 Comment

jeremy Over a year ago

In other words, you do not need to parse it twice.

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