php upload file issue using array

Question

in my form I'm trying to upload multiple or single file using php. So my html table is look like this :

<tr>
<td width="142"><b>Docs</b>
<td width="142"><input type="file" name="files[]" id="project_docs1" class="docfile" /></td>
<td width="142"><input type="file" name="files[]" id="project_docs2" class="docfile" /></td>
<td width="142"><input type="file" name="files[]" id="project_docs3" class="docfile" /></td>
</td>

Now when I upload only one file it's showing me error message like : Invalid Format but it's should be accept one file. it's not require to must be upload all 3 files. Can you tell me why it's showing this error message called Invalid Format ? If upload all 3 files then it's working fine.

and when I press the upload button without upload any file it's showing me value 1 for $noOfUpload variable. why ?

$valid_formats = array("jpg", "png", "gif", "txt", "bmp");
$max_file_size = 1024*100; //100 kb
$path = "project_docs"; // Upload directory
$error =  array();  // load error message
$files_name =  array(); // get uploaded file name

foreach ($_FILES['files']['name'] as $key => $name) {

    $size = $_FILES['files']['size'][$key]. "<br>"; 
    $noOfUpload = count($name);

    if($noOfUpload <= 0){
        $error[] =  "Upload your document/s<br>";
    }elseif(!in_array(pathinfo($name, PATHINFO_EXTENSION), $valid_formats)){
        $error[] = "invalid file formate : $name<br>";

    }

    //$name = md5(uniqid()) . '-' . htmlspecialchars_decode($name);
    $files_name[] = "$name";

}

if(!empty($error)){
    foreach ($error as $e) {
        echo "<div class='error'>$e</div>";
    }   
}else{
    foreach ($files_name as $fn) {  
        echo "$fn<br>";
    }       
}

You help is more appreciate. :)

Nishant Solanki · Accepted Answer · 2015-02-21 07:22:49Z

1

Try this

    if (isset($_FILES))
    {
        $valid_formats = array("jpg", "png", "gif", "txt", "bmp");
        for ($i = 0; $i < count($_FILES['files']['name']); $i++)
        {
           if (in_array(pathinfo($FILES['files']['name'][$i], PATHINFO_EXTENSION), $valid_formats))
          {
             $tmp_path = $_FILES['files']['tmp_name'][$i];
             if ($tmp_path != "")
             {
                 if (move_uploaded_file($tmp_path, $new_path))
                 {
                     //Handle other code here
                 }
                 else
                 {
                     $error[] = ""; //your error handling
                 }
             }
             else
             {
                 $error[] = ""; //your error handling
             }
         }
         else
         {
             $error[] = "invalid file formate : $name<br>";
         }
     }
 }

edited Feb 21, 2015 at 7:22

answered Feb 21, 2015 at 6:46

Nishant Solanki

2,1283 gold badges19 silver badges32 bronze badges

Sign up to request clarification or add additional context in comments.

7 Comments

Shibbir Over a year ago

Ok, I'm trying with this.

Nishant Solanki Over a year ago

@creativeartbd please check the edit, $_FILES['files'] as $file

Nishant Solanki Over a year ago

@creativeartbd the way you are using multiple uploads will return different type of array, my above given code will work for <input type='file' name='files[]' multiple='multiple' />... by using this you can select multiple files in a single file selector by using the ctrl key.. and than use my above given code.

Shibbir Over a year ago

why this line of code is true : $file = $_FILES['files']['name']; if(isset($file) && !empty($file)){ echo "hello file"; }else{ echo "no file"; }

Shibbir Over a year ago

it's showing "hello file" (for example) without upload any file.

|

Sonia Bhatia · Accepted Answer · 2015-02-21 06:39:37Z

0

Your code is run for whole array either it's blank or not. First, count your array then run your code upto that count.

answered Feb 21, 2015 at 6:39

Sonia Bhatia

1461 silver badge16 bronze badges

2 Comments

Nishant Solanki Over a year ago

if he doesnt select the file than also the count of the array will be 3, he have to check the name or other variables of the file is set or not..

Sonia Bhatia Over a year ago

if he doesn't select the file than the count of an array will be 0. like $array_count = $_FILES['files'][$i]['name']; count(array_filter($array_count)); Here $i is total count of files array

Bipin Kareparambil · Accepted Answer · 2015-02-21 06:52:45Z

    <tr>
     <td width="142"><b>Docs</b>
     <td width="142"><input type="file" name="files[]" id="project_docs1" class="docfile" /></td>
    </tr>

PHP Code:

    $valid_formats = array("jpg", "png", "gif", "txt", "bmp");
    $max_file_size = 1024*100; //100 kb
    $path = "project_docs"; // Upload directory
    $error =  array();  // load error message
    $files_name =  array(); // get uploaded file name

    foreach ($_FILES['files']['name'] as $key => $name) {

    $size = $_FILES['files']['size'][$key]. "<br>"; 
    $noOfUpload = count($name);

    if($noOfUpload <= 0){
        $error[] =  "Upload your document/s<br>";
    }elseif(!in_array(pathinfo($name, PATHINFO_EXTENSION), $valid_formats)){
        $error[] = "invalid file format : $name<br>";

    }

    //$name = md5(uniqid()) . '-' . htmlspecialchars_decode($name);
    $files_name[] = "$name";

}

if(!empty($error)){
    foreach ($error as $e) {
        echo "<div class='error'>$e</div>";
    }   
}else{
    foreach ($files_name as $fn) {  
        echo "$fn<br>";
    }       
}

Collectives™ on Stack Overflow

php upload file issue using array

3 Answers 3

7 Comments

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

7 Comments

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related