Getting unexpected value while accessing value from Object in Javascript

Question

I have written a very simple JS program which is not giving expected output.

var p = {
        11735: [{
            d: 46.0,
            z: 06810
        }, {
            d: 30.6,
            z: 07047
        }, {
            d: 36.5,
            z: 07026
        }, {
            d: 36.9,
            z: 07032
        }, {
            d: 43.4,
            z: 07083
        }, {
            d: 32.9,
            z: 07094
        }, {
            d: 35.8,
            z: 07002
        }, {
            d: 39.6,
            z: 06460
        }, {
            d: 43.2,
            z: 06484
        }, {
            d: 15.0,
            z: 11581
        }, {
            d: 48.1,
            z: 07753
        }, {
            d: 37.9,
            z: 06614
        }, {
            d: 27.2,
            z: 10601
        }, {
            d: 0.0,
            z: 11735
        }]
    };
alert(p[11735][1].z);

Expected output should be 07047 but actual output is 3623

I don't know why is it happening. Please help me understand this.

Zach Sadler · Accepted Answer · 2015-02-26 18:55:18Z

3

07047 is interpreted as a base 8 number since it begins with a 0.

07047 (base 8) === 3623 (base 10)

http://www.unitconversion.org/numbers/base-8-to-base-10-conversion.html

If you want 07047 to be the number 7047 in base 10, then simply remove the 0 at the beginning.

answered Feb 26, 2015 at 18:55

Zach Sadler

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9 Comments

Zach Sadler Over a year ago

@Pavan do you understand the issue now?

Pointy Over a year ago

@Jack that will not work in this case, because by the time parseInt() is called it'll be too late.

Jack Over a year ago

@Pointy good point, I suppose he could have them stored as strings and then call parseInt, but if he has access to the data source then he might as well remove the leading 0.

Max Worg Over a year ago

you can pass parseInt() a number and it will convert the value to a string for you so you don't have to store them as strings if you don't want to. parseInt(41, 16) == 65 works just as well as parseInt('41', 16) == 65

Jack Over a year ago

@MaxWorg You can pass it a number, but the problem in this case is that the number in the p object will already have been converted because of the leading zero so it is as pointy mentioned too late.

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