How to find integer array size in java

Question

below is my code which is throwing error:

Cannot invoke size() on the array type int[]

Code:

public class Example{
int[] array={1,99,10000,84849,111,212,314,21,442,455,244,554,22,22,211};    
public void Printrange(){

for (int i=0;i<array.size();i++){
    if(array[i]>100 && array[i]<500)
{
System.out.println("numbers with in range ":+array[i]); 
}


}

Even i tried with array.length() it also throwing the same error. When i used the same with string_name.length() is working fine.

Why it is not working for an integer array?

Arrays does not have a size() method. They have a length field. docs.oracle.com/javase/tutorial/java/nutsandbolts/arrays.html — Alexis C.
– Alexis C., Commented Mar 2, 2015 at 9:15

user1907906 · Accepted Answer · 2015-03-02 09:15:59Z

32

The length of an array is available as

int l = array.length;

The size of a List is availabe as

int s = list.size();

answered Mar 2, 2015 at 9:15

user1907906

Sign up to request clarification or add additional context in comments.

Comments

munmunbb · Accepted Answer · 2017-02-23 19:31:24Z

2

I think you are confused between size() and length.

(1) The reason why size has a parentheses is because list's class is List and it is a class type. So List class can have method size().

(2) Array's type is int[], and it is a primitive type. So we can only use length

answered Feb 23, 2017 at 19:31

munmunbb

41711 silver badges22 bronze badges

Comments

aman_novice · Accepted Answer · 2018-11-08 22:06:27Z

1

Integer Array doesn't contain size() or length() method. Try the below code, it'll work. ArrayList contains size() method. String contains length(). Since you have used int array[], so it will be array.length

public class Example {

    int array[] = {1, 99, 10000, 84849, 111, 212, 314, 21, 442, 455, 244, 554, 22, 22, 211};

    public void Printrange() {

        for (int i = 0; i < array.length; i++) {
            if (array[i] > 100 && array[i] < 500) {
                System.out.println("numbers with in range" + i);
            }
        }
    }
}

edited Nov 8, 2018 at 22:06

aman_novice

1,0473 gold badges13 silver badges31 bronze badges

answered Mar 2, 2015 at 10:34

Suman Behara

1609 bronze badges

1 Comment

E A Over a year ago

array.length is what you want!

Ruchira Gayan Ranaweera · Accepted Answer · 2015-03-02 09:16:15Z

0

There is no method call size() with array. you can use array.length

answered Mar 2, 2015 at 9:16

Ruchira Gayan Ranaweera

35.7k17 gold badges78 silver badges117 bronze badges

Comments

Ankur Singhal · Accepted Answer · 2015-03-02 09:18:03Z

0

Array's has

array.length

whereas List has

list.size()

Replace array.size() to array.length

answered Mar 2, 2015 at 9:18

Ankur Singhal

26.1k17 gold badges92 silver badges129 bronze badges

Comments

Arun Kumar · Accepted Answer · 2015-03-02 09:24:39Z

0

public class Test {

    int[] array = { 1, 99, 10000, 84849, 111, 212, 314, 21, 442, 455, 244, 554,
            22, 22, 211 };

    public void Printrange() {

        for (int i = 0; i < array.length; i++) { // <-- use array.length 
            if (array[i] > 100 && array[i] < 500) {
                System.out.println("numbers with in range :" + array[i]);
            }
        }
    }
}

answered Mar 2, 2015 at 9:24

Arun Kumar

2,9341 gold badge21 silver badges15 bronze badges

Comments

Varun · Accepted Answer · 2017-01-28 19:34:15Z

0

we can find length of array by using array_name.length attribute

int [] i = i.length;

answered Jan 28, 2017 at 19:34

Varun

71 silver badge9 bronze badges

Collectives™ on Stack Overflow

How to find integer array size in java

7 Answers 7

Comments

Comments

1 Comment

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

7 Answers 7

Comments

Comments

1 Comment

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related