is this the right way to do the same?
nsmutablearray *myarray1 //have some data in it
for (int i=0;i< [myarray1 count]; i++)
{
myArray2 = [NSMutableArray array];
[myArray2 addObject:i];
}
and how can i print this value of myarray2.
If you are trying to copy element of one array to other array then use following code:
NSMutableArray *secondArray = [NSMutableArray arrayWithArray:firstArray];
If you want to print element value then depending upon data stored in your array you can print element.
i.e if array contains string object then you can print like this:
for(int i=0;i<secondArray.count;i++)
{
NSLog(@"Element Value : %@",[secondArray objectAtIndex:i]);
}
if array contains any user define object then you can print like this:
for(int i=0;i<secondArray.count;i++)
{
UserDefineObject *obj = [secondArray objectAtIndex:i];
NSLog(@"Element Value with property value: %@",obj.property);
}
The easiest way to create a new array containing the same elements as the old array is to use NSCopying or NSMutableCopying.
NSArray* myArray2 = [myArray1 copy]; // myArray2 is an immutable array
NSMutableArray* myArray3 = [myArray1 mutableCopy]; // myArray3 is an mutable array
If you want to print the contents of an array for debugging purposes:
NSLog(@"myArray2 = %@", myArray2);
If you want prettier printing for a UI, you'll need to iterate through as others have suggested.
myArray2 = [NSMutableArray array];statement outside theforloop. If you did that, your code would work to copy the array, although Jim's solution witharrayWithArray:is better.