How to extract an IP address from an HTML string?

Question

I want to extract an IP address from a string (actually a one-line HTML) using Python.

>>> s = "<html><head><title>Current IP Check</title></head><body>Current IP Address: 165.91.15.131</body></html>"

-- '165.91.15.131' is what I want!

I tried using regular expressions, but so far I can only get to the first number.

>>> import re
>>> ip = re.findall( r'([0-9]+)(?:\.[0-9]+){3}', s )
>>> ip
['165']

But I don't have a firm grasp on reg-expression; the above code was found and modified from elsewhere on the web.

possible duplicate of Regular expression to match hostname or IP Address? — Denis Otkidach
– Denis Otkidach, Commented May 23, 2010 at 16:24

Mark Byers · Accepted Answer · 2010-05-23 07:36:57Z

76

Remove your capturing group:

ip = re.findall( r'[0-9]+(?:\.[0-9]+){3}', s )

Result:

['165.91.15.131']

Notes:

If you are parsing HTML it might be a good idea to look at BeautifulSoup.
Your regular expression matches some invalid IP addresses such as 0.00.999.9999. This isn't necessarily a problem, but you should be aware of it and possibly handle this situation. You could change the + to {1,3} for a partial fix without making the regular expression overly complex.

edited May 23, 2010 at 7:36

answered May 23, 2010 at 7:02

Mark Byers

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3 Comments

rcbevans Over a year ago

You can use the regex expression to accept only valid IP addresses "\\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\b"

RussellStewart Over a year ago

Very nice. For those of you who were interested in the impact of (?:...), you can find it at the docs docs.python.org/2/library/re.html : "(?:...) A non-capturing version of regular parentheses. Matches whatever regular expression is inside the parentheses, but the substring matched by the group cannot be retrieved after performing a match or referenced later in the pattern."

m3nda Over a year ago

@o0rebelious0o Impressive regexp. For easines and in case that you're already using this python solution, you could use ipaddress.ip_address(ip) to check for it.

Snehal · Accepted Answer · 2010-05-23 07:11:32Z

6

You can use the following regex to capture only valid IP addresses

re.findall(r'\b25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?\.25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?\.25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?\.25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?\b',s)

returns

['165', '91', '15', '131']

answered May 23, 2010 at 7:11

Snehal

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1 Comment

Jakob Borg Over a year ago

Technically, this doesn't match valid IP adresses but valid octets. There can be any number of them, which might need to be checked in a separate step.

jdotjdot · Accepted Answer · 2013-01-07 05:42:06Z

5

import re

ipPattern = re.compile('\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}')

findIP = re.findall(ipPattern,s)

findIP contains ['165.91.15.131']

edited Jan 7, 2013 at 5:42

jdotjdot

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answered Jan 7, 2013 at 5:24

Rambo7

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Comments

Mohsen Sarkar · Accepted Answer · 2018-03-13 08:11:59Z

4

You can use following regex to extract valid IP without following errors
1.Some detected 123.456.789.111 as valid IP
2.Some don't detect 127.0.00.1 as valid IP
3.Some don't detect IP that start with zero like 08.8.8.8

So here I post a regex that works on all above conditions.

Note : I have extracted more than 2 millions IP without any problem with following regex.

(?:(?:1\d\d|2[0-5][0-5]|2[0-4]\d|0?[1-9]\d|0?0?\d)\.){3}(?:1\d\d|2[0-5][0-5]|2[0-4]\d|0?[1-9]\d|0?0?\d)

answered Mar 13, 2018 at 8:11

Mohsen Sarkar

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2 Comments

Mohammad Zain Abbas Over a year ago

Can you please elaborate your regex pattern ??

m3nda Over a year ago

@MohammadZainAbbas. I think it would be a so long reply. Feel free to enjoy this interactive explanation -> regexr.com/4r3j3

Artem Kulikov · Accepted Answer · 2015-08-17 04:42:53Z

2

easiest way to find the ip address from the log..

 s = "<html><head><title>Current IP Check</title></head><body>Current IP Address: 165.91.15.131</body></html>"
 info = re.findall(r'[\d.-]+', s)

In [42]: info

Out[42]: ['165.91.15.131']

edited Aug 17, 2015 at 4:42

Artem Kulikov

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answered Aug 17, 2015 at 3:54

user2987237

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2 Comments

rakesh patanga Over a year ago

Could you please explain this [\d.-]+ , '- after . what it will represent

Ricky Levi Over a year ago

[\d.-]+ will grab any number even if the string doesn't contains IPs, i.e: it will grab the IP and the numbers 1 & 2 in a sentence like 104.108.71.62: has versionsr: 1 vs. 2

Gonzalo Cao · Accepted Answer · 2013-01-21 19:23:14Z

1

This is how I've done it. I think it's so clean

import re
import urllib2

def getIP():
    ip_checker_url = "http://checkip.dyndns.org/"
    address_regexp = re.compile ('\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}')
    response = urllib2.urlopen(ip_checker_url).read()
    result = address_regexp.search(response)

    if result:
            return result.group()
    else:
            return None

get_IP() returns ip into a string or None

You can substitute address_regexp for other regular expressions if you prefer a more accurate parsing or maybe change the web service provider.

answered Jan 21, 2013 at 19:23

Gonzalo Cao

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