PHP regular expression to extract date from string

Question

It's nothing that I am with this regular expressions stuff. I don't get the regular expression for my requirement. Here is the string format that I have to split with a regular expression in PHP.

ABCxxxx_ABCDEfghi_YYYYmmddhhmmss.mp4

In this string,

ABC -word(case sensitive)
x -any digit
ABCDEfghi -word(case sensitive)
YYYYmmddhhmmss -timestamp value
.mp4 -word preceded with a dot(.)

All I need is to extract the date from this string.

ie, take YYYYmmdd to a variable.

I know that this is not the way of writing it, but I tried. Here is the attempt:

$s = "ABC0000_ABCDEfghi_20000101223344.mp4";
$regex = "/\ABC[0-9]{4}_ABCDEfghi_&var=[0-9]{8}[0-9]{6}+\.mp4/";
$matches = array();
$s = preg_match($regex, $s, $matches);
print_r($matches[1]);

THE ERROR:

( ! ) Notice: Undefined offset: 1 in D:\wamp\www\Test\regex.php on line 6 Call Stack Time Memory Function Location 1 0.0000 241296 {main}( ) ..\regex.php:0

I am stuck. Please help me with a solution.

Avinash Raj · Accepted Answer · 2015-03-16 05:36:59Z

1

Remove the \ before A

Don't use &var, instead you need to use capturing groups.

$regex = '~ABC[0-9]{4}_ABCDEfghi_([0-9]{8})[0-9]{6}\.mp4~';

Add start ^ and end $ anchors if necessary.

DEMO

$s = "ABC0000_ABCDEfghi_20000101223344.mp4";
$regex = '~^ABC[0-9]{4}_ABCDEfghi_([0-9]{8})[0-9]{6}\.mp4$~';
preg_match($regex, $s, $matches);
print_r($matches[1]);

Output:

20000101

answered Mar 16, 2015 at 5:36

Avinash Raj

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2 Comments

Ataboy Josef Over a year ago

Is it possible to split the same date as YYYY, mm and dd into $matches[] in the same regular expression?

Ataboy Josef Over a year ago

Yes, that was all what I needed for this.

vks · Accepted Answer · 2015-03-16 05:36:28Z

1

(?<=_)\d+(?=\.mp4)

Simply use this.See demo.

https://regex101.com/r/bW3aR1/4

$re = "/(?<=_)\\d+(?=\\.mp4)/";
$str = "ABC0000_ABCDEfghi_20000101223344.mp4";

preg_match_all($re, $str, $matches);

answered Mar 16, 2015 at 5:36

vks

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