PHP Preg_match always return true

Question

im trying to retreive a list of Wordpress Posts with get_posts,

After that, i want to search in the post_content if there any match of a specific string.

right now, my code is:

if(preg_match('/\b[download id="2"]\b/i', $value->post_content)){
       echo('match');
}else{
       echo('nomatch');
}

But it return alway a match.

What i'm doing wrong?

Could you give an example of what you want to match and what you don't want to match. Cuz i can't figure it out with your description — Unex
– Unex, Commented Mar 26, 2015 at 16:49

Styphon · Accepted Answer · 2015-03-26 16:49:57Z

1

Square brackets means to match against any of the characters specified, so in your case it's matching d or o or w or n or l or a or or i or = or " or 2.

If you want to match download id="2" in a string then you need to use /(download id="2")/i. If you want to match [download id="2"] then you need to escape the square brackets like this: /(\[download id="2"\])/i

answered Mar 26, 2015 at 16:49

Styphon

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