Regexp to match multiple Strings - Ruby

Question

Say I have the following array of addresses

array = ["1 New Street, Filton Grove, Bristol BD7 0AA", "2 New Street, Filton Grove, Bristol BD7 0AA", "3 New Street, Filton Grove, Bristol BD7 0AA"]

I would like to check that each item in the array contains the words Filton Grove Bristol, but as there are commas within the address is is throwing me slightly.

How do I ignore the commas and check that each word exists in each iteration of the array

So far I have this

regexp = /^Filton Grove Bristol/i
array.all? { |a| regex =~ a }

But this fails.

Do they ALL contain a comma?

Docteur
– Docteur

2015-04-14 08:57:01 +00:00
Commented Apr 14, 2015 at 8:57 — Docteur
– Docteur, Commented Apr 14, 2015 at 8:57

Sergio Tulentsev · Accepted Answer · 2015-04-14 08:57:23Z

2

You could check for words separately.

regexp_checks = [/Filton/i, /Grove/i, /Bristol/i]
array.all? { |a| regexp_checks.all?{|rgx| a =~ rgx} }

answered Apr 14, 2015 at 8:57

Sergio Tulentsev

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1 Comment

karthik manchala Over a year ago

This is best if you dont want the order of words :)

Yu Hao · Accepted Answer · 2015-04-14 09:00:45Z

2

If the three words must be in the specific sequence, try this:

regexp = /Filton[,\s]+Grove[,\s]+Bristol/i

answered Apr 14, 2015 at 9:00

Yu Hao

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karthik manchala · Accepted Answer · 2015-04-14 09:07:29Z

2

You could also check in this way..

regexp_checks = [/Filton.*?Grove.*?Bristol/i]
array.all? { |a| regexp_checks.all?{|rgx| a =~ rgx} }

Note: Use this only if you want to maintain the order of words appearing. And if order is important and no other words should be allowed in between.. you can use
regexp_checks = [/Filton\W+Grove\W+Bristol/i]

edited Apr 14, 2015 at 9:07

answered Apr 14, 2015 at 8:59

karthik manchala

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Richlewis Over a year ago

Thank You, In my case the order of the words would be quite useful

Narendra Yadala · Accepted Answer · 2015-04-14 09:12:15Z

2

Try the following regex

regexp = /Filton Grove,?\s*Bristol/i

You do not need the ^ in your regex.

edited Apr 14, 2015 at 9:12

answered Apr 14, 2015 at 9:00

Narendra Yadala

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Comments

prgmrDev · Accepted Answer · 2015-04-14 09:53:53Z

1

For all possible use cases

regexp = /Filton[\s,\s]*Grove[\s,\s]*Bristol/i

answered Apr 14, 2015 at 9:53

prgmrDev

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