PHP preg_replace url get parameters in string

Question

Thanks to @s.d.a.p.e I've come a step close but I'm not quite there yet.

What I'm trying to do is replace all instances of a string in a block of text. I want to replace something like this:

user is ?user_id=34&first_name=Ralph so is ?user_id=1 also

With this:

user is /user/34/ so is /user/1/ also

Here is the preg_replace code I'm using:

$pattern = '#\?user_id=([0-9]+)#';
$replace = '/user/$1/';
echo preg_replace($pattern,$replace,$string);

With that pattern I end up with this:

user is /user/34/&first_name=Ralph so is /user/1/ also

Thanks again.

@RST, yes. I was actually going through my history finding close examples. I'll get those posted in a few minutes. — Rob
– Rob, Commented Apr 16, 2015 at 20:41
print preg_replace('#\?user_id=([0-9]+)\&(first_name=(?:.*))#','/user/$1?$2','?user_id=34&first_name=Ralph'); — s.d.a.p.e
– s.d.a.p.e, Commented Apr 16, 2015 at 20:57
preg_replace('~\?user_id\=(\d+)\S*~i', '/user/$1/', $string); — Deadooshka
– Deadooshka, Commented Apr 18, 2015 at 5:48

Pedro Lobito · Accepted Answer · 2015-04-18 04:50:14Z

1

try this:

$string = "user is ?user_id=34&first_name=Ralph so is ?user_id=1 also";
$result = preg_replace('/\?(user)_id=(\d+)(.*?)(?! )/i', '/$1/$2/$3', $string );

echo $result ;

Output:

user is /user/34/&first_name=Ralph so is /user/1/ also

DEMO

edited Apr 18, 2015 at 4:50

answered Apr 18, 2015 at 4:44

Pedro Lobito

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Toto · Accepted Answer · 2015-04-18 08:40:32Z

1

I'd use this:

$string = 'user is ?user_id=34&first_name=Ralph so is ?user_id=1 also';
$pattern = '#\?user_id=([0-9]+)\S*#';
$replace = '/user/$1/';
echo preg_replace($pattern, $replace, $string);

Where \S stands for any character that is not a space.

Output:

user is /user/34/ so is /user/1/ also

answered Apr 18, 2015 at 8:40

Toto

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Pedro Lobito · Accepted Answer · 2015-04-21 19:00:23Z

1

print preg_replace(
   '#\?user_id=([0-9]+)\&(first_name=(?:.*))#',
   '/user/$1?$2',
   '?user_id=34&first_name=Ralph'
);

result :

/user/34?first_name=Ralph  if get it right..

edited Apr 21, 2015 at 19:00

Pedro Lobito

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answered Apr 16, 2015 at 20:59

s.d.a.p.e

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2 Comments

s.d.a.p.e Over a year ago

for /user/34 remove ?$2

Rob Over a year ago

This is extremely close, but when I remove ?$2, it doesn't continue on with the string and stops at /user/34. "user is ?user_id=34&first_name=Ralph and hes a user." is the

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