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I want to sort the array list with having maximum value in first position. Currently I am doing as shown below: 

for (int i = 0; i < str_position.size(); i++) { 

                            int position_id = str_position_id_one_time;
                            position_id--;
                            Log.e("position_id---=------>",""+position_id);
                            str_position_id_one_time = position_id; 
                            array_bitmap_grid_adpater.remove(Integer.parseInt(str_position.get(i)));
                            adapter_GridView.notifyDataSetChanged();

Sort the array list maximum value on first position ex : [0, 1, 5, 3] i need [5, 3, 1, 0]

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  • apply bubble sort algorithm and print in reverse order. Commented Apr 28, 2015 at 5:32

2 Answers 2

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Here's one way for your list:

Collections.sort(list);
Collections.reverse(list);

OR this one line

Collections.sort(unsortedArrayList, Collections.reverseOrder());

First sort it then reverse it ;)

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4 Comments

its not sorting if the array count more that 10 ex : [4, 6, 7, 9, 10, 11, 8, 5, 2, 1] this is sorted array [9, 8, 7, 6, 5, 4, 2, 11, 10, 1]
@user3790247 this happens when you use string array, please confirm
yes im sorting the string array , if i changed to integer means works perfect thanks all
Yes it works great if you're using int array :) Please up-vote and mark as correct so we can help others to find correct solution :)
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One Suggestion :

your_array.sort(function(a, b){return b-a});
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1 Comment

Generally, answers are much more helpful if they include an explanation of what the code is intended to do, and why that solves the problem without introducing others :)

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