Convert Java String to Array

Question

This is a weird problem. Here is my code

 String reply = listen.executeUrl("http://localhost:8080/JavaBridge/reply.php);

executeUrl returns as String object whatever is returned by the reply.php file. Now comes the problem. In reply.php I am returning an PHP array and reply is a String.

When I do

System.out.println("Reply = "+reply);

I get

Reply =       array(2) {  [0]=>  string(14) "Dushyant Arora"  [1]=>  string(19
) "@dushyantarora13 hi"}

But reply is still a String. How do I convert it into a String array or an Array.

thetaiko · Accepted Answer · 2010-06-08 14:57:59Z

8

You might want to try returning a JSON object in reply.php and then importing that into Java using the JSON libraries.

http://www.json.org/java/

reply.php:

<?
...
echo json_encode($yourArray);

In your Java code:

...
JSONArray reply = new JSONArray(listen.executeUrl("http://localhost:8080/JavaBridge/reply.php"));

edited Jun 8, 2010 at 14:57

answered Jun 8, 2010 at 14:50

thetaiko

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1 Comment

polygenelubricants Over a year ago

+1 for JSON! Standard format supported in libraries by both languages!

polygenelubricants · Accepted Answer · 2010-06-08 14:47:56Z

2

There's nothing weird about it at all. You have declared String reply, so of course it's a string. The standard way of splitting a String into a String[] is to use String.split, but I'd seriously consider changing the format of the reply string rather than trying to figure out the regex for the current format, because it's not all that friendly as it is.

answered Jun 8, 2010 at 14:47

polygenelubricants

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Comments

Romain Deveaud · Accepted Answer · 2010-06-08 14:47:42Z

1

You may want to change the behaviour of reply.php, and return a string instead of an array.

Maybe something like

// ...
return implode(" ", $your_reply_array) ;

answered Jun 8, 2010 at 14:47

Romain Deveaud

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2 Comments

Bruce Over a year ago

I need an array on Java side. How do I get that?

Romain Deveaud Over a year ago

Forget that, like thetaiko said JSON is what you need :)

danben · Accepted Answer · 2010-06-08 15:09:26Z

1

Parsing a PHP array with Java is not the cleanest solution, but I can never resist a good regex problem.

public static void main(String[] args) {
    Pattern p = Pattern.compile("\\[\\d+\\]=>  string\\(\\d+\\) \"([^\"]*)\"");
    String input = "      array(2) {  [0]=>  string(14) \"Dushyant Arora\"  [1]=>  string(19" +
            ") \"@dushyantarora13 hi\"}";
    ArrayList<String> list = new ArrayList<String>();
    Matcher m = p.matcher(input);
    while (m.find()) {
        list.add(m.group(1));
    }
    System.out.println(list);
}

[Dushyant Arora, @dushyantarora13 hi]

answered Jun 8, 2010 at 15:09

danben

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