String object to array ruby

Question

I converted my db and the data in one of my tables got changed in the conversion. Basically, I want to go from: "{1,2}" to ["1", "2"] in ruby. Any thoughts?

Also, it wont be just two numbers always, it will vary for each row in the table.

Thanks in advance!

Cary Swoveland · Accepted Answer · 2015-05-03 02:29:00Z

3

"{1,22,33,444}".scan(/\d+/) #=> ["1", "22", "33", "444"]

should do it.

answered May 3, 2015 at 2:29

Cary Swoveland

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2 Comments

user2536065 Over a year ago

Just have to watch out for the "number's" type. The OP didn't specify that it would be necessarily Integers (though it probably would be)

Cary Swoveland Over a year ago

@jphager2, That's true, but the example and reference to "just two numbers" suggested natural numbers to me. If the strings to be captured can be something other than natural numbers, a different regex would of course be required.

Sid · Accepted Answer · 2015-05-03 06:45:02Z

1

You can also use this non-regex solution:

"{1,22,33,444}".delete("{}").split(",")
  #=> ["1", "22", "33", "444"]

edited May 3, 2015 at 6:45

answered May 3, 2015 at 2:52

Sid

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8 Comments

Cary Swoveland Over a year ago

A variant of your approach: "{1,22,33,444}".split(/[{,}]/)[1..-1] #=> ["1", "22", "33", "444"].

user2536065 Over a year ago

Wow. Never knew that two strings literals next to each other on a line would be concatinated! Nice!

Cary Swoveland Over a year ago

@jphager2, see the accepted answer here for more on that. If memory serves, it comes from C/C++. Here Sid could have just written delete("{}").

user2536065 Over a year ago

Thanks for the link. I guess in the end I did know about it, because I've used it through continued lines using '\' but never thought about it.

Sid Over a year ago

@CarySwoveland Thanks for pointing that out, I've edited my answer. Looking back at the ruby docs for #delete method on strings, one thing I dont understand is why "hello".delete("lo","l") returns "heo". Do you know why it acts that way because I would think that it should return "he" as it first deletes "lo" and then "l"?

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