PHP Object loop

Question

I am trying to get specific information from database and specific for each user. I want to loop through an object and get a specific information (string) from 2 different field in database. Each 2 field combine will create a link to download a file.(those file will be located inside project folder)

I need to loop through the database get the field and display it, of course database will containe many link-file.

Here the database structure:

file_id (int)
file_name (name)
file_extension (pdf)
user_id (int)

Here is class file to get full info from user:

    public $file = array();
    public $pdo = '';

    public function __construct($id)
    {
        $this->pdo = new PDO('mysql:host=127.0.0.1;dbname=****', '***', '***', array(PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION));
        $sql = 'SELECT `name`, `file_name`, `file_extention` FROM `users`'
                 .'JOIN `file`'
                 .'ON users.`user_id` = file.`user_id`'
                 .'WHERE users.`user_id` = :id';
        $stmt = $this->pdo->prepare($sql);
        $stmt->execute(array(':id' => $id));
        while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
            $this->file[] = $row;
        }
    }

Here is view class display :

   public function displayFile($link) 
   {
    $output = '';
    $output .= '<p><a href="#"><i class="fa fa-folder"></i>&nbsp&nbsp'. $link.'</a></p><br />';
    return $output;
   }

I need to get a link like :

$link = [file_name].'.'.[file_extension];

Final result for public should be :

link to file 01
link to file 02
link to file 03
etc....

Could you clarify where you are stuck, please? Did you write this code yourself or did someone pass it off to you? — MonkeyZeus
– MonkeyZeus, Commented May 13, 2015 at 13:27
I wrote this code myself. When i construct the link this always take the last link and skip the previous one. — Nicks
– Nicks, Commented May 13, 2015 at 13:30

Honza Haering · Accepted Answer · 2015-05-13 13:29:46Z

1

You almost got it, inside your loop, you create a link like this:

while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
    ...
    $link = $row['file_name'] . '.' . $row['file_extension'];

    // then you can store it in an array:
    $links[] = $link;
    // or call the display function directly:
    $output .= displayFile($link);
    ...
}

answered May 13, 2015 at 13:29

Honza Haering

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DMcP89 · Accepted Answer · 2015-05-13 13:33:30Z

0

Instead of adding the row to your array, build the link and add it.

   while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
                $this->file[] = $row['file_name'].'.'.$row['file_extension'];
    }

answered May 13, 2015 at 13:33

DMcP89

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Nicks · Accepted Answer · 2015-05-13 13:58:26Z

Working code incase someone need it : Thanks to Honza Haering

 public function __construct($id)

{
    public $file = array();
    public $pdo = '';
    $this->pdo = new PDO('mysql:host=127.0.0.1;dbname=project001', 'root', '', array(PDO::ATTR_ERRMODE => PDO::
ERRMODE_EXCEPTION));
    $sql = 'SELECT `name`, `file_name`, `file_extention` FROM `users`'
             .'JOIN `file`'
             .'ON users.`user_id` = file.`user_id`'
             .'WHERE users.`user_id` = :id';
    $stmt = $this->pdo->prepare($sql);
    $stmt->execute(array(':id' => $id));
    while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
        $this->file[] = $row['file_name'] . '.' . $row['file_extention'];
    }
}
public function displayFile() 
{
    $link = $this->file;
    $output = '';
    foreach($link as $row) {
    $output .= '<p><a href="#"><i class="fa fa-folder"></i>&nbsp&nbsp'. $row.'</a></p><br />';
    }
    return $output;
}

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