Displaying all list items while using a foreach loop in php

Question

I need some assistance to create a foreach loop which will display each array item from an array with three items. Currently, my code correctly displays the first and last item; however, it does not display the second item.

The loop will be used to generate a navbar from the items in the array.

Here is my PHP code:

<ul>
<?php
    $navOptions = array('home','services','contact');

    foreach($navOptions AS $navOption) {
        if ($navOption == $currentPage) {
            echo '<li><a href ="' . $navOption . '.php class="current">' . ucfirst($navOption) . '</li></a>';
        } else {
            echo '<li><a href="' . $navOption . '.php>' . ucfirst($navOption) . '</li></a';
        }

    }
?>
</ul>

This code generates a list of links like this:

Home
Contact

However, it does not generate the "Services" list item.

A side note: the $currentPage variable is declared as a global variable on each individual html page ie, within index.php, services.php, contact.php.

taxicala · Accepted Answer · 2015-05-19 18:16:45Z

1

You are missing some double quotes, and the closing > of the else statement, should be as follows:

$navOptions = array('home','services','contact');

    foreach($navOptions AS $navOption) {
        if ($navOption == $currentPage) {
            echo '<li><a href="' . $navOption . '.php" class="current">' . ucfirst($navOption) . '</li></a>';
        } else {
            echo '<li><a href="' . $navOption . '.php">' . ucfirst($navOption) . '</li></a>';
        }

    }

answered May 19, 2015 at 18:16

taxicala

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