I got an array with Objects. Now I want to check if all of those Objects are instance of MyObject.
Is there a better option than this:
boolean check = true;
for (Object o : justAList){
if (!(o instanceof MyObject)){
check = false;
break;
}
}
If you don't like the loop, you can always do this in Java 8:
Using ArrayList
List<Object> justAList = new ArrayList<>();
// Add items here...
return justAList.stream().allMatch(o -> o instanceof MyObject);
Using normal array
Object[] justAList = new Object[10];
// Set items here...
return Arrays.stream(justAList).allMatch(o -> o instanceof MyObject);
EDIT:
The above suggestion will only be useful to you if you want to perhaps improve code readability and/or make it more succinct. But don't think that it avoids having to perform a loop. It will still perform a loop, you just won't see it. So don't expect this to perform any better than what you already have.
list, so I assumed you were using an ArrayList. I'll edit my post to give you both an ArrayList version, and an array version. EDIT: Sorry, I just noticed that the text of your post did say array :) It would have helped to have included the type in your code though.It might not relate to this particular problem, but it is a good practice to use polymorphism instead of checking the type in an if condition. Like
public void handle(MyObject object) {
doSomething
}
public void handle(Object object) {
doSomething
}
handle(o);
Depending on your requirements, you could use a List<MyObject> and other Lists with their respective types in the first place instead of an Object-Array in which you put everything.
