How to catch a SyntaxError in JavaScript

Question

I am trying to catch a Syntax error in my code, but it does not get into catch block

( function(){
try {

 throw fn(){};  // I am trying to generate some syntax error here

}catch (exception){
    console.log(exception.message);
  }

})();

Edited

If you notice here the wrong syntax is inside the try block, so as a javascript theory it has to first go inside catch block, then whats use of a built-in object SyntaxError

( function(){
try {

throw fn(){};
}catch (exception){
   if(exception instanceof SyntaxError)
   console.log("Syntax Exception occured" + exception.message); 
}
})();

but this is not handled in program instead I am able to see "Uncaught SyntaxError" directly in console

Uncaught SyntaxError: Unexpected token {
    at Object.InjectedScript._evaluateOn (<anonymous>:895:140)
    at Object.InjectedScript._evaluateAndWrap (<anonymous>:828:34)
    at Object.InjectedScript.evaluate (<anonymous>:694:21)

possible duplicate of Syntax errors can be caught in JavaScript? — CodingIntrigue
– CodingIntrigue, Commented Jul 2, 2015 at 11:23

ben · Accepted Answer · 2015-07-02 11:24:57Z

1

You cannot catch syntax error simply because the whole script is not evaluated (due to the syntax error... Only thing I can imagine is to get the code as string, then pass it to eval() and wrap the eval into a try catch...

But earth will collapse if you do that...

var test="var x= 1.5.5;"; //this is a syntax error
var test2="var x=1;"
try {
  eval(test)
  alert(test + ' is a valid script')
} catch(e) {
  alert(test + ' is not a valid script')
}
try {
  eval(test2)
  alert(test2 + ' is a valid script')
} catch(e) {
  alert(test2 + ' is not a valid script')
}

edited Jul 2, 2015 at 11:24

answered Jul 2, 2015 at 11:22

ben

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