Bash Formatting Output in Hex Bytes

Question

Suppose I have a output in stdout like this:

e28f6001
e12fff16
2210
4679
df01
6c656873

How can I pipe this in bash so I can append \x for each byte. I want the the output like this:

\xe2\x8f\x60\x01\xe1\x2f\xff\x16\x22\x10 ...

sed -e 's/../\\x&/g' though that won't join the lines.

Etan Reisner
– Etan Reisner

2015-07-02 13:50:17 +00:00
Commented Jul 2, 2015 at 13:50 — Etan Reisner
– Etan Reisner, Commented Jul 2, 2015 at 13:50
As usual, what have you tried ?

Brian Agnew
– Brian Agnew

2015-07-02 13:51:23 +00:00
Commented Jul 2, 2015 at 13:51 — Brian Agnew
– Brian Agnew, Commented Jul 2, 2015 at 13:51
sed -r 's/([a-fA-F0-9]{2})/\\x\1/g' file | tr -d '\n'

anubhava
– anubhava

2015-07-02 13:53:13 +00:00
Commented Jul 2, 2015 at 13:53 — anubhava
– anubhava, Commented Jul 2, 2015 at 13:53
Seriously, show a little effort please. tr -d '\n '

ShellFish
– ShellFish

2015-07-02 13:59:35 +00:00
Commented Jul 2, 2015 at 13:59 — ShellFish
– ShellFish, Commented Jul 2, 2015 at 13:59

Arjun Mathew Dan · Accepted Answer · 2015-07-02 13:59:12Z

2

tr -d '\n' < File | sed 's/.\{2\}/\\x&/g'

Remove newline first. Then substitute every 2 characters (.\{2\}) with \x followed by the 2 characters (& => the matched pattern which will be those 2 characters).

answered Jul 2, 2015 at 13:59

Arjun Mathew Dan

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1 Comment

Tom Fenech Over a year ago

You probably picked up the downvote when your answer (which you have since edited within the 5 minute window) consisted of a single line of code with no explanation.

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