android unable to parse json data android

Question

I am unable to parse JSON data ,it always give me [] whenever i am parsing i have checked on jsonlint.com for valid json ,it returns the correct data

url is http://egravity.in/csvupload/hello.php/ and in params i am using param.add(new BasicNameValuePair("id", "14")); thus i expect url to be=http://egravity.in/csvupload/hello.php/?id=14

package com.example.prototype.utility;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.List;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.conn.DefaultClientConnection;
import org.json.JSONException;
import org.json.JSONObject;

import android.os.StrictMode;
import android.util.Log;
import android.widget.Toast;

@SuppressWarnings({ "deprecation", "unused" })
public class JSONUtil {

    JSONObject result;
    String temp;
    String t;
    InputStream is;
    String exception="";
    static String json = "";
    static JSONObject jObj = null;

  public String setConnection(String url,String method,List <NameValuePair>params){
        if (android.os.Build.VERSION.SDK_INT > 9) {
            StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
            StrictMode.setThreadPolicy(policy);
        }

        DefaultHttpClient client=new DefaultHttpClient();
        if(method.equalsIgnoreCase("post")){



            HttpResponse httpResponse = null;

            try {

                HttpPost httpPost = new HttpPost(url);
               httpPost.setEntity(new UrlEncodedFormEntity(params));

                t= httpPost.getURI().toString();
    Log.e("ur", t);
                httpResponse = client.execute(httpPost);
                Log.e("response",httpResponse.toString());
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();
                Log.e("content_bestfrag ","input stream have "+is.available()  );

        if(is==null)
                Log.e("content ","input stream is null");

        else
            Log.e("content_bestfrag ","input stream is not null "+is.available()  );



            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
                exception+=e.getMessage()+"  ";
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
                exception+=e.getMessage()+"  ";

            }

        }


        try{
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is));


            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            json = sb.toString();

            }catch(Exception e){
                Log.e("Buffer Error", "Error converting result " + e.getMessage());
            }

            Log.e("json", json);
            return json;
    }





}

Whenever i print json(a string containg data returned) it shows [] instead of data please help me...!!!

can you see your logcat Log.e("ur", t); what's it's value? — Rustam
– Rustam, Commented Aug 10, 2015 at 12:19
yes bt it is not adding params to it ,it is like 08-10 17:51:27.149: E/ur(21896): egravity.in/csvupload/hello.php — AnonymousDev
– AnonymousDev, Commented Aug 10, 2015 at 12:21

shaikhmanzoor · Accepted Answer · 2015-08-10 12:28:15Z

1

You should make a get request rather than post try this code

    HttpClient client = new DefaultHttpClient();


    URI website = new URI("http://egravity.in/csvupload/hello.php/?id=14"); 
    HttpGet request = new HttpGet();
    request.setURI(website);
    HttpResponse response = client.execute(request);
    response.getStatusLine().getStatusCode();

    in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
    StringBuffer sb = new StringBuffer("");
    String l = "";
    String nl = System.getProperty("line.separator");
    while ((l = in.readLine()) != null) {
        sb.append(l + nl);
    }
    in.close();
    data = sb.toString();

edited Aug 10, 2015 at 12:28

answered Aug 10, 2015 at 12:20

shaikhmanzoor

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3 Comments

AnonymousDev Over a year ago

how will i set dynamically passed params like ,we set in post

shaikhmanzoor Over a year ago

You can use stringbuffer to append the paramter to your url

shaikhmanzoor Over a year ago

Example: String paramString = URLEncodedUtils.format(params, "utf-8"); StringBuffer stringBuffer = new StringBuffer(URL); stringBuffer .append("?"); stringBuffer .append(paramString); final URL as String stringBuffer .toString()

Threat70 · Accepted Answer · 2015-08-10 12:21:47Z

0

You use HttpPost, but in url like "http://egravity.in/csvupload/hello.php?id=14" - HttpGet with param id=14

answered Aug 10, 2015 at 12:21

Threat70

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Comments

kfmes · Accepted Answer · 2015-08-10 12:28:55Z

0

EntityUtils.toString() is easy to gets HttpResponse string.

HttpPost post = new HttpPost(url);
HttpClient client = new DefaultHttpClient();

post.setEntity(new UrlEncodedFormEntity(params1, charset));
HttpResponse resp = client.execute(post);
String strResp = EntityUtils.toString(resp.getEntity());

JSONObject jsonResp = new JSONObject(strResp);
System.out.println(jsonResp.toString(4));

answered Aug 10, 2015 at 12:28

kfmes

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