Cannot run perl script from PHP

Question

I have made a perl script which I would like to run from PHP.

When I do a normal example like

PHP:

exec("perl test.pl",$output);
echo '<pre>'; print_r(array_values($output)); echo '</pre>';

PERL:

#!/usr/bin/perl -s
print "Hiii. This is perl executing in PHP";

And it prints out: Hiii. This is perl executing in PHP in PHP

But when I add my other Perl script (test2):

#!/usr/bin/perl -s

# Function definition
use test_sub qw( :all ) ;

use strict;
use warnings;

if ($ARGV[0] eq "te") 
{
  printf("te chosen to(%d)\n",$ARGV[1]);
  te($ARGV[1]);
}

And the new PHP looks like:

exec("perl test2.pl",$output);
echo '<pre>'; print_r(array_values($output)); echo '</pre>';

I know that there should be a warning atleast eventhough i dont use any arguments, but nothing appears to be in the $output.

Even with arguments in PHP:

exec("perl test2.pl te 1",$output);
echo '<pre>'; print_r(array_values($output)); echo '</pre>';

Nothing appears. I have tried to see if the file in executable with the function

is_executable('test2.pl')

Which it is.

This runs on a Raspberry PI 2 with Arch and I do not know if this could have any impact?

The other perl file which is referred to is:

package test_sub; 

use strict;
use warnings;

use Exporter qw(import);
use Time::HiRes qw(usleep);

our @EXPORT_OK = qw(te);
our %EXPORT_TAGS = (all => \@EXPORT_OK );

sub te {
  my @var = @_;
  printf("settingup te for %d",$var);
}

I have checked in the terminal for it self and here it works as intended. But I cannot get it to work through PHP.

Any help would be much appreciated.

Update 1

I have found out that if I add the line:

use test_sub qw( :all ) ;

To the test.pl script which worked it stops giving an output asswell.

Why do you have the -s flag enabled in your Perl shebang?

simbabque
– simbabque

2015-08-12 10:05:10 +00:00
Commented Aug 12, 2015 at 10:05 — simbabque
– simbabque, Commented Aug 12, 2015 at 10:05

Malli Paritala · Accepted Answer · 2015-08-12 10:05:16Z

There are two problems here:

First:

Below line

printf("settingup te for %d",$var);

should be changed to

printf("settingup te for %d",@var);

There was no $var variable initialized to print, its @var array you are using in your subroutine.

Second:

You should know how to write a simple php script.

#!/usr/bin/php

<?php
exec("perl test.pl te 1",$output);
echo '<pre>'; print_r(array_values($output)); echo '</pre>';
?>

This works fine for me and output:

<pre>Array
(
    [0] => te chosen to(1)
    [1] => settingup te for 1
)
</pre>

perl script:

#!/usr/bin/perl -s

# Function definition
use test_sub qw( :all ) ;

use strict;
use warnings;

if ($ARGV[0] eq "te") 
{
  printf("te chosen to(%d)\n",$ARGV[1]);
  te($ARGV[1]);
}

perl module:

package test_sub; 

use strict;
use warnings;

use Exporter qw(import);
use Time::HiRes qw(usleep);

our @EXPORT_OK = qw(te);
our %EXPORT_TAGS = (all => \@EXPORT_OK );

sub te {
  my @var = @_;
  printf("settingup te for %d",@var);
}

php code:

#!/usr/bin/php

<?php
exec("perl test.pl te 1",$output);
echo '<pre>'; print_r(array_values($output)); echo '</pre>';
?>

That should work fine for you as well.

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