Using objects in an NSArray

Question

Hey I have these UIView objects in a dictionary I have created as such:

- (NSArray *)createNumberOfViews:(NSInteger)number
{
NSMutableArray *viewArray = [NSMutableArray array];
for(NSInteger i = 0; i < number; i++)
{
    UIView *view = [[UIView alloc] init];
    // any setup you want to do would go here, e.g.:
    // view.backgroundColor = [UIColor blueColor];
    [viewArray addObject:view];
    [view release];
}
return viewArray;
}

So now I need to access each member of this array and add them each to a superview, any ideas how i might go ahead and do this?

A quick glance at the documentation for NSArray (and UIView if necessary) will show you the way — Brian
– Brian, Commented Jul 8, 2010 at 19:06
It is really a matter of style/preference, but unless the returned array will be modified, you should return an immutable array.. return [NSArray arrayWithArray:viewArray];. Otherwise you should change your method declaration to return NSMutableArray. — ohhorob
– ohhorob, Commented Jul 8, 2010 at 20:42
@ohhorob: That really is a matter of preference. The fact that his array is an NSMutableArray is an implementation detail, just like the fact that all NSArrays are actually NSMutableArrays (seriously, check [[NSArray arrayWithObject:@"Hello"] isKindOfClass:[NSMutableArray class]]). His method signature is accurate and his method implementation is efficient, so there's really no need to complicate things or expose private implementation details IMO. — Chuck
– Chuck, Commented Jul 8, 2010 at 22:34
I think I was pretty clear that my comment "is really a matter of style/preference"! Personally, my reasoning of why the declaration should "declare" (yes, really!) the actual return type of a mutable/immutable class cluster is it can provide semantics useful to reading and using the code. At the end of the day it's not a big deal, but a useful habit nonetheless. — ohhorob
– ohhorob, Commented Jul 8, 2010 at 22:51

Chuck · Accepted Answer · 2010-07-08 19:19:11Z

6

Just get the result of that method and enumerate through it:

for (UIView *view in [self createNumberOfViews:42]) {
    [yourSuperview addSubview:view];
}

answered Jul 8, 2010 at 19:19

Chuck

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Glenn Smith · Accepted Answer · 2010-07-08 22:10:34Z

2

If you have NSArray *views = [self createNumberOfViews:10] then use

[(UIView *) addSubview[views objectAtIndex:number]];

That should work. Comment if it doesn't, but this is pretty basic.
Edit: Oops. Didn't quite understand. Fixed up code :P

edited Jul 8, 2010 at 22:10

answered Jul 8, 2010 at 19:14

Glenn Smith

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1 Comment

ohhorob Over a year ago

Not quite. @Ollie asks about adding each view in the array to a superview; you are adding subviews to each view in the array

Reena · Accepted Answer · 2010-07-09 06:06:42Z

0

Please try this

for(NSInteger i = 0; i < [viewArray count]; i++)
{
     UIView *view = (UiView*)[viewArray objectAtIndex:i];
     [parentView addObject:view];   // parentView = your super view
}

answered Jul 9, 2010 at 6:06

Reena

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