I finally understood lambdas! or so I thought
why does this not work:
Example 1:
for x in range(18, 101):
print("Man's age: ", x, "Women's age: ", lambda x:x//2+9(x))
yet this does:
Example 2:
for x in range(18, 101):
print("Man's age: ", x, "Women's age: ", (lambda x:x//2+9)(x))
does this mean putting a lambda on a parenthesis is the equivalent of calling it? and putting another open/close parenthesis next to it means it is it's arguments?
In your first example, you are printing a lambda function definition
if the same if you assign it to a variable and try to print it.
v = lambda x:x//2+9(x)
print v
>>function <lambda> at 0x10c32aaa0
If you want to execute it, you need to do v(x)
But, you will get an error because 9(x) statement, is trying to call a function using an int.
The proper way to use it
v = lambda x:x//2+9
print v(2)
>>10
Lambda defines the function but doesn't actually call it. It's the difference of just "f" and "f(x)". A clearer solution would look like:
func = lambda x: x//2+9
for x in range(18, 101):
print("Man's age: ", x, "Women's age: ", func(x))
(x)calls it andxis the parameter. In the first case without parameter, how would python know you didn't mean to call9as a function?9(x)?