Php Regex Expression

Question

I have this regex expression:

$str = preg_replace_callback('@((https?://)?([-\w]+\.[-\w\.]+)+\w(:\d+)?(/([-\w/_\.]*(\?\S+)?)?)*)@', function

($matches){return en($matches[1]);}, $str);

Against this html code:

<iframe src="//example.com/hello.php"></iframe>

the output is:

 <iframe src="//maskedurl.php?l=kdsdhkhdkshdkhsdskhd"></iframe>

How can i have the regex not output the 2 slashes, // ? and have it only display:

<iframe src="maskedurl.php?l=kdsdhkhdkshdkhsdskhd"></iframe>

yes I know it's missing the http: but that is out of my control

even then, this regex101 shows that your group is capturing that you expect to capture. — Shawn Mehan
– Shawn Mehan, Commented Oct 12, 2015 at 15:56
@dustmouse He's not using the regexp to parse HTML, he's using it to parse a URL. — Barmar
– Barmar, Commented Oct 12, 2015 at 15:56
2 options: (re)move the outer brackets, because there // is being grouped, which you don't want. Alternatively: return a substr from within the callback (ie substr($matches[1], 2)) — Elias Van Ootegem
– Elias Van Ootegem, Commented Oct 12, 2015 at 16:01

Philipp · Accepted Answer · 2015-10-12 16:00:19Z

2

You have to modify the (https?://) part, so that it accepts also the //. This could result in something easy as ((?:https?:)?//) or (https?://|//)

So in the end you have the following regex

'@((https?://|//)?([-\w]+\.[-\w\.]+)+\w(:\d+)?(/([-\w/_\.]*(\?\S+)?)?)*)@'

php

$str = preg_replace_callback('@((https?://|//)?([-\w]+\.[-\w\.]+)+\w(:\d+)?(/([-\w/_\.]*(\?\S+)?)?)*)@', function ($matches){return en($matches[0]);}, $str);

edited Oct 12, 2015 at 16:00

answered Oct 12, 2015 at 15:57

Philipp

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4 Comments

Elias Van Ootegem Over a year ago

OP isn't worried about the http(s) not being there, he's worried about the callback returning the first two characters (ie //)

Philipp Over a year ago

Then he should use $matches[0]

Elias Van Ootegem Over a year ago

No, read the question carefully: he doesn't want to return the first two chars: he needs to either not capture the first part of the match, or return substr($match[1], 2);

Philipp Over a year ago

His problem is, he want to mask the url, but the first two // are ignored and never get replaces by his regex. So he would also the first two // in his regex. If the protocol should be ignored, he could/have to do this in his callback function.

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