PHP String/Variable To Array And Check String/Variable Null

Question

Hello I want create string to array. I have 4 variables:

    <?php 
      $name = "John";
      $address = "Moscow";
      $born_date = "13-11-1995";
      $color = "red"; 

      $join = $name.":".$address.":".$born_date.":".$color;
      $array = explode(':', $join);
      print_r ($array);
    ?>

This array result is:

Array ( [0] => John [1] => Moscow [2] => 1995-11-13 [3] => red )

When I change $color variable to null like $color="";

This result like this:

Array ( [0] => John [1] => Moscow [2] => 1995-11-13 [3] => )

I want array number 3 not to show. I want if all $variable == NULL / $variable=="undefined" / $varable=""

Show like this:

Array ( [0] => John [1] => Moscow  [2] => 1995-11-13)

The array shows only variable filled.

Use array_filter($array); or use if conditions. Or make your array using if conditions and $array[] = $name; etc...not sure you need to create a string just to explode() it to an array when you can just make an array. — Rasclatt
– Rasclatt, Commented Oct 20, 2015 at 21:57

Don't Panic · Accepted Answer · 2015-10-20 22:15:11Z

1

I'm not sure what your requirements are, but it seems strange to create this array by joining the variables together and then exploding them. You could just add them directly to the array, and add the color conditionally:

$array = array($name, $address, $born_date);
if ($color) {
    $array[] = $color;
}

If you need all of the elements to be added conditionally, you can create an array containing all of them and then use array_filter as Rasclatt suggested to eliminate the empty ones.

$array = array($name, $address, $born_date, $color);
$array = array_filter($array);

If it is important that the keys remain sequential, you can use

$array = array_values(array_filter($array));

edited Oct 20, 2015 at 22:15

answered Oct 20, 2015 at 22:00

Don't Panic

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6 Comments

Maestro Vladimir Over a year ago

i try your code, and i change $color="" and $born_date=""

Maestro Vladimir Over a year ago

this born_date always show, so i must create else if again ?

Don't Panic Over a year ago

Do you mean that each of the elements should only be included in the array if they are not null and != ""?

Maestro Vladimir Over a year ago

yes. if $born_date="" / $color="" / $name="" / address="" this resut array not show

Maestro Vladimir Over a year ago

if $born_date and $color null > Array ( [0] => John [1] => Moscow )

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